CODEWITHSUNDEEP
angulartypescriptangular12typescript4.0
Jorge Mantiñán
Jorge Mantiñán

Reputation: 3

Argument of type 'string | null' is not assignable to parameter of type 'string'. Type 'null' is not assignable to type 'string'. Angular 12

JSON.parse(sessionStorage.getItem('owner'))
==> Argument of type 'string | null' is not assignable to parameter of type 'string'. Type 'null' is not assignable to type 'string'.

And the return null;
==> Type 'null' is not assignable to type 'string'.

public get owner(): Owner{
if(this._owner != null){
  return this._owner;
} else if (this._owner == null && sessionStorage.getItem('owner') != null){
  this._owner = JSON.parse(sessionStorage.getItem('owner')) as Owner; // <== HERE
  return this._owner;
}
return new Owner();

}

public get token(): string{
if (this._token != null) {
  return this._token;
} else if (this._token == null && sessionStorage.getItem('token') != null) {
  this._token = sessionStorage.getItem('token') as string;
  return this._token;
}
return null;   // <== HERE: Type 'null' is not assignable to type 'string'.

}

Upvotes: 0

Views: 1107

Answers (1)

Kelvin Schoofs
Kelvin Schoofs

Reputation: 8718

You define token() as returning only a string, yet you're trying to return null. You can change the definition to return string | null:

public get token(): string | null {
    if (this._token != null) {
        return this._token;
    } else if (this._token == null && sessionStorage.getItem('token') != null) {
        this._token = sessionStorage.getItem('token') as string;
        return this._token;
    }
    return null;
}

Of course the code using this getter needs to account for that.

Upvotes: 3

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