Reputation: 14039
I am trying to create a Pandas DataFrame
from a NumPy masked array, which I understand is a supported operation. This is an example of the source array:
a = ma.array([(1, 2.2), (42, 5.5)],
dtype=[('a',int),('b',float)],
mask=[(True,False),(False,True)])
which outputs as:
masked_array(data=[(--, 2.2), (42, --)],
mask=[( True, False), (False, True)],
fill_value=(999999, 1.e+20),
dtype=[('a', '<i8'), ('b', '<f8')])
Attempting to create a DataFrame
with pd.DataFrame(a)
returns:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-40-a4c5236a3cd4> in <module>
----> 1 pd.DataFrame(a)
/usr/local/anaconda/lib/python3.8/site-packages/pandas/core/frame.py in __init__(self, data, index, columns, dtype, copy)
636 # a masked array
637 else:
--> 638 data = sanitize_masked_array(data)
639 mgr = ndarray_to_mgr(
640 data,
/usr/local/anaconda/lib/python3.8/site-packages/pandas/core/construction.py in sanitize_masked_array(data)
452 """
453 mask = ma.getmaskarray(data)
--> 454 if mask.any():
455 data, fill_value = maybe_upcast(data, copy=True)
456 data.soften_mask() # set hardmask False if it was True
/usr/local/anaconda/lib/python3.8/site-packages/numpy/core/_methods.py in _any(a, axis, dtype, out, keepdims, where)
54 # Parsing keyword arguments is currently fairly slow, so avoid it for now
55 if where is True:
---> 56 return umr_any(a, axis, dtype, out, keepdims)
57 return umr_any(a, axis, dtype, out, keepdims, where=where)
58
TypeError: cannot perform reduce with flexible type
Is this operation indeed supported? Currently using Pandas 1.3.3 and NumPy 1.20.3.
Update
Is this supported? According to the Pandas documentation here:
Alternatively, you may pass a numpy.MaskedArray as the data argument to the DataFrame constructor, and its masked entries will be considered missing.
The code above was my asking the question "What will I get?" if I passed a NumPy masked array to Pandas, but that was the result I was hoping for. Above was the simplest example I could come up with.
I do expect each Series/column in Pandas to be of a single type.
Update 2
Anyone interested in this should probably see this Pandas GitHub issue; it's noted there that Pandas has "deprecated support for MaskedRecords".
Upvotes: 1
Views: 1715
Reputation: 231385
If the array has a simple dtype, the dataframe creation works (as documented):
In [320]: a = np.ma.array([(1, 2.2), (42, 5.5)],
...: mask=[(True,False),(False,True)])
In [321]: a
Out[321]:
masked_array(
data=[[--, 2.2],
[42.0, --]],
mask=[[ True, False],
[False, True]],
fill_value=1e+20)
In [322]: import pandas as pd
In [323]: pd.DataFrame(a)
Out[323]:
0 1
0 NaN 2.2
1 42.0 NaN
This a
is (2,2), and the result is 2 rows, 2 columns
With the compound dtype, the shape is 1d:
In [326]: a = np.ma.array([(1, 2.2), (42, 5.5)],
...: dtype=[('a',int),('b',float)],
...: mask=[(True,False),(False,True)])
In [327]: a.shape
Out[327]: (2,)
The error is the result of a test on the mask. flexible type
refers to your compound dtype
:
In [330]: a.mask.any()
Traceback (most recent call last):
File "<ipython-input-330-8dc32ee3f59d>", line 1, in <module>
a.mask.any()
File "/usr/local/lib/python3.8/dist-packages/numpy/core/_methods.py", line 57, in _any
return umr_any(a, axis, dtype, out, keepdims)
TypeError: cannot perform reduce with flexible type
The documented pandas feature clearly does not apply to structured arrays. Without studying the pandas code I can't say exactly what it's trying to do at this point, but it's clear the code was not written with structured arrays in mind.
The non-masked part does work, with the desired column dtypes:
In [332]: pd.DataFrame(a.data)
Out[332]:
a b
0 1 2.2
1 42 5.5
Using the default fill
:
In [344]: a.filled()
Out[344]:
array([(999999, 2.2e+00), ( 42, 1.0e+20)],
dtype=[('a', '<i8'), ('b', '<f8')])
In [345]: pd.DataFrame(a.filled())
Out[345]:
a b
0 999999 2.200000e+00
1 42 1.000000e+20
I'd have to look more at ma
docs/code to see if it's possible to apply a different fill to the two fields. Filling with nan
doesn't work for the int field. numpy
doesn't have pandas'
int none. I haven't worked enough with that pandas feature to know whether the resulting dtype is still int, or it is changed to object.
Anyways, you are pushing the bounds of both np.ma
and pandas
with this task.
The default fill_value is a tuple, one for each field:
In [350]: a.fill_value
Out[350]: (999999, 1.e+20)
So we can fill the fields differently, and make a frame from that:
In [351]: a.filled((-1, np.nan))
Out[351]: array([(-1, 2.2), (42, nan)], dtype=[('a', '<i8'), ('b', '<f8')])
In [352]: pd.DataFrame(a.filled((-1, np.nan)))
Out[352]:
a b
0 -1 2.2
1 42 NaN
Looks like I can make a structured array with a pandas dtype, and its associated fill_value:
In [363]: a = np.ma.array([(1, 2.2), (42, 5.5)],
...: dtype=[('a',pd.Int64Dtype),('b',float)],
...: mask=[(True,False),(False,True)],
fill_value=(pd.NA,np.nan))
In [364]: a
Out[364]:
masked_array(data=[(--, 2.2), (42, --)],
mask=[( True, False), (False, True)],
fill_value=(<NA>, nan),
dtype=[('a', 'O'), ('b', '<f8')])
In [366]: pd.DataFrame(a.filled())
Out[366]:
a b
0 <NA> 2.2
1 42 NaN
Upvotes: 3
Reputation: 260790
The question is what would you expect to get? It would be ambiguous for pandas to convert your data.
If you want to get the original data:
>>> pd.DataFrame(a.data)
a b
0 1 2.2
1 42 5.5
If you want to consider masked values invalid:
>>> pd.DataFrame(a.filled(np.nan))
BUT, for this you should have all type float in the masked array
Upvotes: 0