Reputation: 79
I have 3 databases, where I need to create database A, then database B, then create the linking database A_B.
I use mysqli transactions in PHP, there is a weird case(this is the first time i use php transactions), where it never rollback when it fails, case like database A fail to insert, but B still created. and A_B created incorrectly.
mysqli_begin_transaction($link);
try{
$sql = "INSERT INTO A (
....)
VALUES
(?, ?, ?, ?, ?, ?, ?, ?, ?,?,?,?,?);";
$stmt = mysqli_prepare($link,$sql);
mysqli_stmt_bind_param($stmt,"sssssssssssss",
....
);
mysqli_stmt_execute($stmt);
$param_new_A_Rec = mysqli_insert_id($link);
for($i = 0; $i < $tot; $i++){
$sql = "INSERT INTO B (..)
VALUES
(?, ?, ?, ?, ?, ?, ?, ?, ?,?,?,?);";
$stmt = mysqli_prepare($link,$sql);
mysqli_stmt_bind_param($stmt,"ssssssssssss",
...
);
mysqli_stmt_execute($stmt);
$param_new_B_Rec = mysqli_insert_id($link);
$sql = "INSERT INTO A_B (
param_new_A_Rec,
param_new_B_Rec,
....
(?,?,?,?,?,?);";
$stmt = mysqli_prepare($link,$sql);
mysqli_stmt_bind_param($stmt,"ssssss",
....
);
mysqli_stmt_execute($stmt);
}
mysqli_commit($link);
}catch (mysqli_sql_exception $exception) {
mysqli_rollback($link);
throw $exception;
}
Why if A failed, it never hit the rollback() and it created the incorrect A_B and B data? Did I miss anything here? any help would be greatly appreciated!
Upvotes: 0
Views: 271
Reputation: 79
In fact, I need to add this
"mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);"
Now it is catching the invalid use case:
PHP Fatal error: Uncaught mysqli_sql_exception: Incorrect integer value: '' for column 'boolean_X' at row 1 in yourFile.php
Upvotes: 1