CODEWITHSUNDEEP
sed
Kevin
Kevin

Reputation: 3358

Replace a string by a file which name equals regex capture group

I have a file named foo where I want to replace the line containing the following regex match:

<script.*src="(.*)".*><\/script>

With the content of a file which name equals the first capture group in the regex above. For example, I might have the following line in foo:

<script type="text/javascript" src="bar.js"></script>

Which I want to replace with the content from the file bar.js.

I want to somehow open the file referenced by the first capture group. This is what I have so far:

sed -r "s/<script.*src=\"(.*)\".*><\/script>/$(cat \1) /" foo

But I am getting cat: 1: No such file or directory.

Even when I try to manually specify the file I want to open I get an Error which I can't understand:

sed -r "s/<script.*src=\"(.*)\".*><\/script>/$(cat bar.js)/" test.txt

Error:

sed: -e expression #1, char 53: unterminated `s' command

Upvotes: 1

Views: 38

Answers (1)

KamilCuk
KamilCuk

Reputation: 141493

First, get what file to open:

file=$(sed -En 's|.*<script.*src="(.*)".*></script>.*|\1|p' test.txt)

Then you can delete the line and read the file in sed using r command and delete line with d.

sed -E -e '\|.*<script.*src="(.*)".*></script>.*|{ r '"$file" -e 'd;}' test.txt

You can use e extension to GNU sed and execute a script instead of the part.

sed -E 's|<script.*src="(.*)".*></script>|cat \1|e' test.txt

You should strongly consider using an XML aware parser, like xmlstarlet or xmllint, and consider using a real programming language, at least scripting one like python or perl.

Upvotes: 2

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