CODEWITHSUNDEEP
djangourl
Reventlow
Reventlow

Reputation: 167

Django default arguments in URL

I have a url path that looks like this:

path("asset_app/asset/<str:location>/", views.AssetListView.as_view(), name="asset_app_asset_list"),

I want that if location is not set that it sets

location = "all"

How do I do that?

Upvotes: 1

Views: 1429

Answers (2)

Niel Godfrey P. Ponciano
Niel Godfrey P. Ponciano

Reputation: 10709

Use regex with django.urls.re_path to capture an optional field location within the URL. Then, define its default value in the view.

urls.py

from django.urls import re_path

from my_app.views import get_asset

urlpatterns = [
    re_path(r"asset_app/asset/(?P<location>\w+)?", get_asset),
]

views.py

from django.http import HttpResponse

def get_asset(request, location="all"):
    print(f"{location=}")
    return HttpResponse(location)

Output:

$ curl http://127.0.0.1:8000/asset_app/asset/
all
$ curl http://127.0.0.1:8000/asset_app/asset/whatever
whatever
$ curl http://127.0.0.1:8000/asset_app/asset/wherever/
wherever

Logs:

location='all'
[04/Aug/2021 07:40:27] "GET /asset_app/asset/ HTTP/1.1" 200 3
location='whatever'
[04/Aug/2021 07:40:40] "GET /asset_app/asset/whatever HTTP/1.1" 200 8
location='wherever'
[04/Aug/2021 07:42:00] "GET /asset_app/asset/wherever/ HTTP/1.1" 200 8

Related reference:

Upvotes: 3

Ashish Nautiyal
Ashish Nautiyal

Reputation: 931

Any how in this case as suggested by @bdbd you have to use 2 url patterns one with location argument and other without it which will point to same view like below:

path("asset/<str:location>/", views.AssetListView.as_view(),name="asset_app_asset_list"),
    path("asset/", views.AssetListView.as_view(),name="asset_app_asset_withoutlist"),

In your CBV you can access location by get method on kwargs with default value as 'all' if not passed as arguments in url:

location = self.kwargs.get('location','all')

Upvotes: 1

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