CODEWITHSUNDEEP
javamongodbspring-boot
Srikar
Srikar

Reputation: 371

Spring boot mongodb not saving uniqueId

I'm working on a Spring application and I'm using MongoDB as my database. I have a document structure where I am saving the id of another document to use as a reference. This id is an objectId and then save it using

mongoOperations.save(message)

It is using the same objectId as the one I'm saving for reference to create _id field for this newly created document. So my document is like this

{
   "_id":{
      "$oid":"610a03578c9e4937107b6501"
   },
   "ConversationId":{
      "$oid":"610a03578c9e4937107b6501"
   },
   "Author":"author",
   "Body":"hey there",
   "CreatedAt":{
      "$date":{
         "$numberLong":"1628171556888"
      }
   }
}

As you can see that both the ids for _id and ConversationId are the same. I have tried saving ConversationId as a string and it still does the same. Not sure what mistake I'm making.

{
   "_id":{
      "$oid":"610a03578c9e4937107b6501"
   },
   "ConversationId": "610a03578c9e4937107b6501",
   "Author":"author",
   "Body":"hey there",
   "CreatedAt":{
      "$date":{
         "$numberLong":"1628171556888"
      }
   }
}

This is my model class

@Document(collection = "messages")
public class Message {
    @Id
    private String id;

    @Field("ConversationId")
    private String conversationId;

    @Field("Author")
    private String author;

    @Field("Body")
    private String body;

    @Field("CreatedAt")
    private Instant createdAt;

}

COnversationId in the above model class id an objectId and I tried saving it as a string as mentioned above so It was set to type String here. I have also tried making it ObjectId and still the same issue persists.

How to make it create a unique _id for each record and not use conversationId as its id.

Upvotes: 0

Views: 1146

Answers (1)

Abinash
Abinash

Reputation: 301

I think you need to change id to _id. Attaching reference below

@Document(collection = "messages")
public class Message {
    
    private String _id;

    @Field("ConversationId")
    private String conversationId;

    @Field("Author")
    private String author;

    @Field("Body")
    private String body;

    @Field("CreatedAt")
    private Instant createdAt;

}

Upvotes: 1

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