CODEWITHSUNDEEP
javaspringspring-beanspring-profiles
dhalfageme
dhalfageme

Reputation: 1545

Spring bean depending on multiple profiles

I have to create a bean depending of whether one of 2 possible profiles is active, or a different bean if none of that profiles is active. I have the following:

    @Profile("!A & !B")
    @Bean(name = "myBean")
    @Autowired
    public Object myBean() {
        ...
    }

    @Profile({"A", "B"})
    @Bean(name = "myBean")
    @Autowired
    public Object myBean() {
        ...
    }

This code is working only if no profile A or B is active. To make it work when either A or B are active, I have to switch the order of the bean declaration.

I've tried declaring the beans in different files and it seems t obe working, but I do not understand why this not.

Also I don't understand why "!A & !B" notation seems to be working but "A | B" doest not work so I have to use {"A", "B"} in that case.

Could you explain why having them in the same files only works for the first bean declared and the notations concern?

Thanks

Upvotes: 0

Views: 785

Answers (1)

Dmitrii Bocharov
Dmitrii Bocharov

Reputation: 935

you can simply test your profile expression with org.springframework.core.env.Profiles. For example:

Set<String> activeProfiles = new HashSet<>();
activeProfiles.add("A");
activeProfiles.add("B");

System.out.println(Profiles.of("!A & !B").matches(activeProfiles::contains)); //false
System.out.println(Profiles.of("A", "B").matches(activeProfiles::contains)); // true

Now to your code

1.

This code is working only if no profile A or B is active

Set<String> activeProfiles = Collections.emptySet();

System.out.println(Profiles.of("!A & !B").matches(activeProfiles::contains)); // true
System.out.println(Profiles.of("A", "B").matches(activeProfiles::contains)); // false

So the first bean is active.

2.

To make it work when either A or B are active, I have to switch the order of the bean declaration

no, you don't need to switch anything:

Set<String> activeProfiles = new HashSet<>();
activeProfiles.add("A");

System.out.println(Profiles.of("!A & !B").matches(activeProfiles::contains)); //false
System.out.println(Profiles.of("A", "B").matches(activeProfiles::contains)); // true

So the second bean will always be active.

3.

"A | B" also works without any problem similarly to "A", "B":

Set<String> activeProfiles = new HashSet<>();
activeProfiles.add("A");

System.out.println(Profiles.of("A | B").matches(activeProfiles::contains)); // true
System.out.println(Profiles.of("A", "B").matches(activeProfiles::contains)); // true

Upvotes: 1

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