CODEWITHSUNDEEP
javaandroidhashmap
Vivek Modi
Vivek Modi

Reputation: 7261

Sorting the Map in descending order based on the value and sort the key in ascending order if value is duplicate

I am using map interface to read from a file and then store the values in that as a key value pair.

Map<String, Integer> map = new HashMap<>();

The value is

A 25
D 10
B 15
E 15
C 17

I want to first sort by value in descending order Sorting the Map<Key,Value> in descending order based on the value . This will help to achieve the order in descending order. But if the value are duplicate i want to sort by key in ascending order.

Expected Output

A 25
C 17
B 15
E 15
D 10

Does any one know how to achieve this .

Upvotes: 0

Views: 1960

Answers (2)

Eritrean
Eritrean

Reputation: 16498

As an alternative to the accepted answer, I would extract the comparators which IMO makes it more readable, i.e to something like:

Map<String, Integer> map = Map.of("A", 25, "D", 10, "B", 15, "E", 15, "C", 17);

Comparator<Map.Entry<String,Integer>> byValueDesc = Map.Entry.comparingByValue(Comparator.reverseOrder());
Comparator<Map.Entry<String,Integer>> byKeyAsc = Map.Entry.comparingByKey();

Map<String, Integer> result =

    map.entrySet()
            .stream()
            .sorted(byValueDesc.thenComparing(byKeyAsc))
            .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (e1,e2)->e1, LinkedHashMap::new));

Upvotes: 1

Unmitigated
Unmitigated

Reputation: 89374

You can use Comparator.comparing and thenComparing to sort in the correct order. Streams can be used to sort and collect the new Map to a LinkedHashMap to retain the new order.

Map<String, Integer> map = Map.of("A", 25, "D", 10, "B", 15, "E", 15, "C", 17);
Map<String, Integer> result = map.entrySet().stream()
    .sorted(Comparator.<Map.Entry<String, Integer>>comparingInt(Map.Entry::getValue)
       .reversed().thenComparing(Map.Entry::getKey))
    .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, 
         (a,b)->b, LinkedHashMap::new));
System.out.println(result);

Demo

Upvotes: 1

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