CODEWITHSUNDEEP
javascript
DarnellG1999
DarnellG1999

Reputation: 37

My JavaScript variable will not change the position of the image

let h;
function getRandomIntH() {
return Math.round(Math.random() * 250);}
h = getRandomIntH();

$('#gamespace').append('<img src="transparent.gif" style="left: 100px; top: h; width: 100px; height: 100px;">');

I made a function above that makes a random number, but whenever I try and use it to move my image, it inputs as zero instead of the number stored in the variable.

Upvotes: 0

Views: 35

Answers (1)

Illusion705
Illusion705

Reputation: 451

Replace the last line with this so that you're using the value from the h variable instead of setting top to the string "h":

$('#gamespace').append(`<img src="transparent.gif" style="left: 100px; top: ${h}px; width: 100px; height: 100px;">`);

Upvotes: 1

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