Reputation: 96
I needed to see the image of a sequence, that's why I chose Python, I got in trouble along the way, that I do not use np.linspace
, so the points in the loop are not connected, but I needed to points get connected like they do in np.linspace
like they are in a line, but I have no idea how to implement this particular sequence.
the sequence :
$${a_n} = 1 + \sum_{n=1}^{\infty}\frac{1}{n!}$$
= 2 + 1/2! + 1/3! +...+1/n!
y = 1
fac = 1
for n in range(80) :
fac = fac * (n+1)
y = y + 1 / fac
plt.plot(n , y , alpha = 0.5 , color = 'red' , linestyle = 'solid' ,
linewidth = 2 , marker = '.' , markersize = 2 ,
markerfacecolor = 'blue' , markeredgecolor = 'blue' )
plt.ylim([-1,4])
plt.savefig('Ascending Highly bounded sequence convergence.png')
plt.clf() #clear figure
Any help is appreciated.
Upvotes: 0
Views: 194
Reputation: 330
The reason why you don't see a line connecting the points is that you call the plot
function for every point. Because of this, matplotlib plots lots of single points with no connections in between.
To get a line between the points you have to call the plot
function with a collection of data points.
from matplotlib import pyplot as plt
X = range(80)
Y = []
y = 1
fac = 1
for n in X:
fac = fac * (n+1)
y = y + 1 / fac
Y.append(y)
plt.plot(X, Y, alpha = 0.5 , color = 'red' , linestyle = 'solid' ,
linewidth = 2 , marker = '.' , markersize = 2 ,
markerfacecolor = 'blue' , markeredgecolor = 'blue' )
plt.ylim([-1,4])
plt.savefig('Ascending Highly bounded sequence convergence.png')
plt.clf() #clear figure
Upvotes: 1