CODEWITHSUNDEEP
swifturluitextview
swifthing
swifthing

Reputation: 550

Bug with "URL" in shouldInteractWith method

I'm trying to catch the YouTube URL in UITextView with this delegate method to open it on Youtube app:

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
    if URL.absoluthePath.contains("youtube.com"), let youtubeURL = URL(string: "youtube://" + id) {
        UIApplication.shared.open(youtubeURL)
    }
}

And I have this error:

Cannot call value of non-function type 'URL'

Because Xcode thinks I'm using 'URL' variable instead of using URL(string: "")! declaration

Upvotes: 0

Views: 574

Answers (2)

vadian
vadian

Reputation: 285290

There are 3 issues in your code, but first of all this is a pretty bad naming by Apple. The internal parameter label should be url (lowercased). But as internal parameter labels are arbitrary, you can change the signature yourself to

func textView(_ textView: UITextView, 
                shouldInteractWith url: URL, 
                in characterRange: NSRange, 
                interaction: UITextItemInteraction) -> Bool {

The other issues are:

  • You have to return a Bool value.
  • There is no API absoluthePath in URL, you mean absoluteString

A more efficient domain check is to use the host parameter of the URL

func textView(_ textView: UITextView, shouldInteractWith url: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
    if url.host?.hasSuffix("youtube.com") == true, let youtubeURL = URL(string: "youtube://" + id) {
        UIApplication.shared.open(youtubeURL)
        return true
    }
    return false
}

Upvotes: 2

Raja Kishan
Raja Kishan

Reputation: 19044

You can use Foundation.URL

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
        if let youtubeURL = Foundation.URL(string: "youtube://" + id), URL.absoluteString.contains("youtube.com")  {
            UIApplication.shared.open(youtubeURL)
        }
    }

Upvotes: 1

Related Questions