CODEWITHSUNDEEP
typescript
Alwaysblue
Alwaysblue

Reputation: 11830

Type Promise<any> have no call signatures

I want to return an async function after 300ms.

In order to do that I thought about creating a promise which I resolve after 300 ms

const justLogDataFromForms = async (index, key, currentValue, payload) => {

      const  dummyPromise:Promise<any> = new Promise((resolve, reject) => {
        setTimeout(() => {
          resolve(true);
        }, 300);
      });
   await dummyPromise()
return 
}

but this throws error

Type Promise have no call signatures.

Can someone explain me the error and let me know how I can fix it? Also, is there a better way to return an async function after x amount of time after it is called?

Upvotes: 0

Views: 11951

Answers (2)

katopz
katopz

Reputation: 671

You can use

await Promise.all([dummyPromise]);

This should work in some case that really need Promise as variable(s).

Upvotes: 0

Tobias S.
Tobias S.

Reputation: 23835

Your variable dummyPromise is a Promise and not a Function so it can not be called. Just remove the parenthesis to await the Promise or don't use a variable at all:

await new Promise((resolve, reject) => {
    setTimeout(() => {
        resolve(true);
    }, 300);
});

Upvotes: 2

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