Reputation: 1
Say that we have an interface:
public interface SomeInterface {
public void A();
public void B();
}
and we have a class:
public class SomeClass {
public void A(){...};
private class SomeInnerClass {
public void B(){...};
}
}
And I need SomeClass to implement SomeInterface, but the required method "B" in SomeClass is implemented in an inner class. What can I do to make SomeClass successfully implement SomeInterface?
Upvotes: 0
Views: 58
Reputation: 1617
Inside SomeClass
create an instance of the SomeInnerClass
and use its implementation for B() method.
like that:
public class SomeClass {
private SomeInnerClass someInnerClass = new SomeInnerClass();
public void A(){
... // self implementation
};
public void B(){
someInnerClass.B(); // Inner class implementation
};
private class SomeInnerClass {
public void B(){...};
}
}
Upvotes: 1