CODEWITHSUNDEEP
python
HJRW
HJRW

Reputation: 13

Loop through nested dictionary, replacing values with items from a list

I am working with a json file that I have now converted to a nested dictionary with the following structure:

dictionary = {
     '4123bf9f': {'date': '', 'link': '', 'topic': ''},
     '45361a6c': {'date': '', 'link': '', 'topic': ''},
     '4d521c71': {'date': '', 'link': '', 'topic': ''},
     '5b00c155': {'date': '', 'link': '', 'topic': ''},
     '875737f4': {'date': '', 'link': '', 'topic': ''},
     '90a64c61': {'date': '', 'link': '', 'topic': ''}
} etc

I am trying to loop through the nested dictionary and change the values for the keys, using items from a list.

For example:

topics = ['1', '2', '3', '4', '5 ', '6']

When integrated would become:

dictionary = {
     '4123bf9f': {'date': '', 'link': '', 'topic': '1'},
     '45361a6c': {'date': '', 'link': '', 'topic': '2'},
     '4d521c71': {'date': '', 'link': '', 'topic': '3'},
     '5b00c155': {'date': '', 'link': '', 'topic': '4'},
     '875737f4': {'date': '', 'link': '', 'topic': '5'},
     '90a64c61': {'date': '', 'link': '', 'topic': '6'}
} etc

I have tried a few different approaches but each has resulted in the same output. I realised the code below is probably too simplistic an approach but for sake of clarity of my problem, the following code:

def update_dic(dictionary):
    for k, v in dictionary.items():
        dictionary[k].update({"topic": n for n in topics})

Results in this output

dictionary = {
     '4123bf9f': {'date': '', 'link': '', 'topic': '6'},
     '45361a6c': {'date': '', 'link': '', 'topic': '6'},
     '4d521c71': {'date': '', 'link': '', 'topic': '6'},
     '5b00c155': {'date': '', 'link': '', 'topic': '6'},
     '875737f4': {'date': '', 'link': '', 'topic': '6'},
     '90a64c61': {'date': '', 'link': '', 'topic': '6'}
} etc

Is it possible to loop through my nested dictionary, replacing "topic" with a distinct value from my list? I have considered trying to make each page in my dictionary a class but was unsure if this was an appropriate method

Any help with this would be greatly appreciated

Upvotes: 0

Views: 566

Answers (3)

ListenSoftware Louise Ai Agent
ListenSoftware Louise Ai Agent

Reputation: 4233

dictionary = {
 '4123bf9f': {'date': '', 'link': '', 'topic': ''},
 '45361a6c': {'date': '', 'link': '', 'topic': ''},
 '4d521c71': {'date': '', 'link': '', 'topic': ''},
 '5b00c155': {'date': '', 'link': '', 'topic': ''},
 '875737f4': {'date': '', 'link': '', 'topic': ''},
 '90a64c61': {'date': '', 'link': '', 'topic': ''}
}
topics = ['1', '2', '3', '4', '5 ', '6']
topic=iter(topics)
for key in dictionary.keys():
     dictionary[key]['topic']=next(topic)
print(dictionary)

output:

 {'4123bf9f': {'date': '', 'link': '', 'topic': '1'}, '45361a6c': {'date': '', 'link': '', 'topic': '2'}, '4d521c71': {'date': '', 'link': '', 'topic': '3'}, '5b00c155': {'date': '', 'link': '', 'topic': '4'}, '875737f4': {'date': '', 'link': '', 'topic': '5 '}, '90a64c61': {'date': '', 'link': '', 'topic': '6'}}

Upvotes: 0

Kelly Bundy
Kelly Bundy

Reputation: 27588

Just another way:

topic = iter(topics)
for d in dictionary.values():
    d['topic'] = next(topic)

And another:

for d, d['topic'] in zip(dictionary.values(), topics):
    pass

Upvotes: 1

Barmar
Barmar

Reputation: 780798

Your dictionary comprehension is creating dictionary elements for every item in the list each time. But since you give them all the same key topic, only the last one is in the resulting dictionary. That's why you keep getting "topic": 6.

Use zip() to iterate through the dictionary keys and list elements in parallel, rather than nesting them. And there's no need to use update() if you're just setting one key of the dictionary, just assign to that key.

def update_dic(dictionary):
    for k, v in zip(dictionary, topics):
        dictionary[k]['topic'] = v

Upvotes: 2

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