Reputation: 1
I’m looking to use frappe.db.delete to remove the most recently modified record in a custom table, Warehouse Locations. I want to limit the delete to only one record that matches some filters.
The table is a child table, if that matters.
I am not clear on how to filter one record, based on the “modified” value. I tried:
frappe.db.delete(‘Warehouse Locations’,
{“warehouse”: warehouse,
“parent”: item_code,
“shelf”: shelf,
“modified”:("=",last_record_to_keep[0].modified)})
I am getting a syntax error when I run the above query.
Upvotes: 0
Views: 3180
Reputation: 11
I think the solution answered by @ChillarAnand is helpful.
Instead, I would like to give a different way to solve the problem you faced. Per your question, the goal is to delete only one record from Warehouse Locations (Child Table).
# 1. Get the parent document for the warehouse location.
parent_doc = frappe.get_doc("Doctype", docname)
# 2. iterate through the child table rows to find the row meet your filter
# and assign to row_to_detele for late use or you can delete straight away
row_to_delete = ""
for row in parent_doc.warehouse_locations:
if row.modified == last_record_to_keep[0].modified:
row_to_delete = row.name
break
# 3. to remove the child table from the parent doc method
parent_doc.remove(row_to_delete)
For the document of parent_doc.remove()
, you can find it through the below github path: https://github.com/frappe/frappe/blob/6b91ade73c07dc1c070ed137cf54a29a3e7b0993/frappe/model/base_document.py#L210 (7 Oct, 2021)
Upvotes: 1
Reputation: 29514
First, filter out the record to be deleted using ORM by running
record = frappe.get_list('Warehouse Locations', order_by='-modified')[0]
Once you filtered it out, you can delete it using frappe.db.delete.
frappe.db.delete('Warehouse Locations', record)
Upvotes: 1