CODEWITHSUNDEEP
javajsonhttpjackson
jenigen
jenigen

Reputation: 147

How I can get List object from JSON instead of a LinkedHashMap?

I have this method which should return different objects from JSON, depending on the type of class in the argument.I tryed it to return a list of objects based on the argument, but I get only LinkedHashMap into ArrayList.

I searched a lot, but everywhere in the solutions the class type is hard-coded.

Is there a way to solve this problem without hard code?

 public static <T> List<T> getObjects(Class<T> c) {
    CloseableHttpClient rest =  HttpClientSessionSingleton.getInstance().getHttpClient();
    String urlRequest = (host + "/" +
            c.getSimpleName().toLowerCase() + "s");

    HttpGet httpGet = new HttpGet(urlRequest);
    try (CloseableHttpResponse response = rest.execute(httpGet)) {
        HttpEntity entity = response.getEntity();
        String jsonString = EntityUtils.toString(entity);

        List<T> listObjectFromJson = new ObjectMapper().readValue(jsonString, new TypeReference<List<T>>(){});

        return listObjectFromJson;
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

I want to just pass the class type and get objects through one method.

[
{
"id": "73cbc0b5-3dd5-49c4-97cb-6225a19122b5",
"name": "Management",
"fields": [
{
"id": "c2d740d5-4d47-42ae-b616-977b40327812",
"name": "newField1"
}
]
},
{
"id": "dd74384b-717d-4368-b0e4-3f441d5b1ffc",
"name": "IT",
"fields": []
},
{
"id": "03304335-d7d7-46ca-8075-8d5e9feb43c6",
"name": "hhh",
"fields": []
},
{
"id": "e11b4c3f-080e-490d-8ef4-ea301d551a5d",
"name": "NEWWWWW",
"fields": []
},
{
"id": "fec7eeb0-0845-49be-be14-6cdb5fcd3575",
"name": "NEWWWWW",
"fields": []
},
{
"id": "50dfea14-f30a-448c-99df-10bf01d088fa",
"name": "NEWWWWW",
"fields": []
},
{
"id": "a4a1224e-7c66-484c-ae87-dc2ecc058c36",
"name": "NEWWWWW",
"fields": []
}
]

I get this exception when my object has a relationship

Unrecognized field "fields" (class model.orm.Department), not marked as ignorable (2 known properties: "id", "name"]) at [Source: (String)"[{"id":"73cbc0b5-3dd5-49c4-97cb-6225a19122b5","name":"Management","fields":[{"id":"c2d740d5-4d47-42ae-b616-977b40327812","name":"newField1"}]},{"id":"dd74384b-717d-4368-b0e4-3f441d5b1ffc","name":"IT","fields":[]},{"id":"03304335-d7d7-46ca-8075-8d5e9feb43c6","name":"hhh","fields":[]},{"id":"e11b4c3f-080e-490d-8ef4-ea301d551a5d","name":"NEWWWWW","fields":[]},{"id":"fec7eeb0-0845-49be-be14-6cdb5fcd3575","name":"NEWWWWW","fields":[]},{"id":"50dfea14-f30a-448c-99df-10bf01d088fa","name":"NEWWWWW","fie"[truncated 84 chars]; line: 1, column: 77] (through reference chain: java.util.ArrayList[0]->model.orm.Department["fields"]) at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from

Upvotes: 1

Views: 1103

Answers (1)

dariosicily
dariosicily

Reputation: 4547

You can construct a new JavaType parametric type passing as an argument the List.class to the ObjectMapper.html#getTypeFactory method like below:

public static <T> List<T> getObjects(Class<T> c) throws IOException {
    //omitted the lines before creating the mapper including the jsonstring
    ObjectMapper mapper = new ObjectMapper();
    JavaType type = mapper.getTypeFactory().constructParametricType(List.class, c);
    
    return mapper.readValue(jsonString, type);
}

Upvotes: 1

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