CODEWITHSUNDEEP
pythonplotly
illhahb
illhahb

Reputation: 81

How can I change the histogram label in x axis and add a trend line to the histogram

I am plotting a frequency histogram, and I want the x_axis to show the range of each bar, eg.[0-9],[10-19]... rather than 50, 100, 150, 200. I also want to add a trend line to this histogram like the example below. Please help!

import plotly.express as px
df = px.data.tips()
fig = px.histogram(df, x=data, color_discrete_sequence=['purple'])
fig.update_layout(bargap=0.01)
fig.show()

enter image description here

example: enter image description here

Upvotes: 1

Views: 1259

Answers (2)

gangappa
gangappa

Reputation: 1

import seaborn as sns 

x = [100,300,200,500,400,300,100,700,1000,1200,3000,2000,2500,3500,4000,4500,5000,150]

sns.set_style('darkgrid')
 
sns.distplot(x)

Use the above code you will get a bell curve. Install the seaborn before using the above code

use the below command

pip install seaborn

Upvotes: 0

Rob Raymond
Rob Raymond

Reputation: 31236

you can go back to basics and use pandas cut() and value_counts()

import pandas as pd
import numpy as np
import plotly.express as px

SIZE = 5
df = px.data.tips()
df = (
    pd.cut(
        df["total_bill"],
        bins=np.arange(0, df["total_bill"].max() + SIZE, SIZE, dtype=int),
    )
    .value_counts()
    .sort_index()
    .reset_index()
    .assign(label=lambda d: d["index"].apply(lambda x: f"{x.left} to {x.right}"))
)
px.bar(df, x="label", y="total_bill", color_discrete_sequence=["purple"]).update_layout(
    bargap=0.01
).add_traces(
    px.line(df, x="label", y="total_bill").update_traces(line={"shape": "spline"}).data
)

enter image description here

Upvotes: 1

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