CODEWITHSUNDEEP
rust
Muhammad Lukman Low
Muhammad Lukman Low

Reputation: 8533

Sort then dedup a rust vector of integer in one line

I want to sort then dedup a vector of i32 in rust:

fn main() {
    let mut vec = vec![5,5,3,3,4,4,2,1,2,1];
    
    vec.sort().collect().dedup();
    println!("{:?}", vec);
}

This code does not work, but if the dedup part is done this way, it's fine:

vec.sort();
vec.dedup();

How do I do sort and dedup in one line in my example ?

Upvotes: 1

Views: 597

Answers (1)

Peter Hall
Peter Hall

Reputation: 58715

With itertools, you can do:

use itertools::Itertools;

fn main() {
    let mut vec = vec![5,5,3,3,4,4,2,1,2,1];
    
    vec = vec.into_iter().sorted().dedup().collect();
    println!("{:?}", vec);
}

It really depeonds on why you think you need a one-liner though. If it's actually because you need a single expression then you can use a block:

vec = {
    vec.sort();
    vec.dedup();
    vec
};

Upvotes: 7

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