CODEWITHSUNDEEP
c#.netwinformsimagedatagridview
Sebastian Busek
Sebastian Busek

Reputation: 1032

Problem with Image in DataGridView

Good morning,

I want to show image (16*16px png file) in DataGridView. This Grid has 3 columns: text cell, text cell, image cell. Here is sample, how I try set image:

    private void showData(List<Item> collection)
    {
        gwQuestions.AutoGenerateColumns = false;
        gwQuestions.DataSource = addNotSet(collection);

        foreach (DataGridViewRow row in gwQuestions.Rows)
        {
            DataGridViewImageCell cell = row.Cells[2] as DataGridViewImageCell;
            cell.ValueType = typeof(System.Drawing.Image);
            if (collection[row.Index].Result)
            {
                cell.Value = (System.Drawing.Image)Properties.Resources.Check;
            }
            else
            {
                cell.Value = (System.Drawing.Image)Properties.Resources.Cancel;
            }
        }
    }

But in grid i show only red cross on paper, like File not found error. Can you help me please?

Upvotes: 2

Views: 3795

Answers (2)

bgmCoder
bgmCoder

Reputation: 6370

Salvete! I was looking for a similar answer. If you don't mind my vb, try this post (where I answered myself...). The code shows how to load an image from resource into a datagridview.

How to dynamically swap a string for an image in Datagridview?

Upvotes: 0

David Hall
David Hall

Reputation: 33183

This should work if you put your logic to assign the image within the CellFormatting event of the DataGridView:

dataGridView1.CellFormatting += dataGridView1_CellFormatting;

void dataGridView1_CellFormatting(object sender, DataGridViewCellFormattingEventArgs e)
{            
    if (dataGridView1.Columns[e.ColumnIndex].Name == "ImageColumnName")
    {
        if (collection[e.RowIndex].Result)
        {
            e.Value = (System.Drawing.Image)Properties.Resources.Check;
        }
        else
        {
            e.Value = (System.Drawing.Image)Properties.Resources.Cancel;
        }
    }
}

Also note that you set e.Value rather than cell.Value here.

Upvotes: 1

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