CODEWITHSUNDEEP
python
شیوا پاساراد
شیوا پاساراد

Reputation: 63

How to split a column into different parts with different sizes?

I have a column whose values are lists. as you see in the following image: columns image

I want the "sequence_movie_ids" column which is a list to be split into two columns, a column comprised of all the values except the last element of the list and another comprised the last element of the list. How can I do this?

Upvotes: 2

Views: 71

Answers (2)

tdy
tdy

Reputation: 41487

If type(df['sequence_movie_ids'].iloc[0]) returns list:

  • Either use the Series.str accessor to split the lists:

    df['all_but_last'] = df['sequence_movie_ids'].str[:-1]
df['only_last'] = df['sequence_movie_ids'].str[-1]

  • Or use Series.apply:

    df['all_but_last'] = df['sequence_movie_ids'].apply(lambda x: x[:-1])
df['only_last'] = df['sequence_movie_ids'].apply(lambda x: x[-1])

If type(df['sequence_movie_ids'].iloc[0]) returns str, that means they are strings that just look like lists.

In that case, first parse them into real lists using ast.literal_eval:

from ast import literal_eval
df['sequence_movie_ids'] = df['sequence_movie_ids'].apply(literal_eval)

And then use the all_but_last and only_last code from above.

Upvotes: 2

ali.k.mirzaei
ali.k.mirzaei

Reputation: 43

if its a real list and not string, you can do like this: a = sequence_movie_ids[:len-1] and b = sequence_movie_ids[len-1]

Upvotes: 1

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