CODEWITHSUNDEEP
pythonpython-3.x
sivaperumal10000
sivaperumal10000

Reputation: 69

How to get the individual words from a string?

input = (Columbia and (India  or Singapore) and Malaysia)

output = [Columbia, India, Singapore, Malaysia]

Basically ignore the python keywords and brackets

I tried with the below code, but still not able to eliminate the braces.

import keyword

my_str=input()
l1=list(my_str.split(" "))
l2=[x for x in l1 if not keyword.iskeyword((x.lower()))]
print(l2)

Upvotes: 1

Views: 86

Answers (2)

S.B
S.B

Reputation: 16496

try this one:

import re
from keyword import iskeyword

inp = '(Columbia and (India or Singapore) and Malaysia)'

c = re.compile(r'\b\w+\b')

print([i.group() for i in c.finditer(inp) if not iskeyword(i.group().lower())])

output :

['Columbia', 'India', 'Singapore', 'Malaysia']

without regex :

from keyword import iskeyword

inp = '(Columbia and (India or Singapore) and Malaysia)'

res = []
for i in inp.split():
    stripped = i.strip('()[]{}')
    if not iskeyword(stripped):
        res.append(stripped)

print(res)

Upvotes: 2

Vulwsztyn
Vulwsztyn

Reputation: 2261

import keyword
my_str=input()
my_str = re.sub(r'[\(\)\[\]{}]','',my_str)
l1=list(my_str.split(" "))
l2=[x for x in l1 if not keyword.iskeyword((x.lower()))]
print(l2)

re.sub(r'[\(\)\[\]{}]','',my_str)

This will replace all kinds of braces with empty strings (thus removing them).

Upvotes: 2

Related Questions