CODEWITHSUNDEEP
mathmaple
user16769489
user16769489

Reputation:

In Maple, How to divide the numbers of an array (list or vector or matrix) with the numbers of an array of equal number of rows and columns?

In Maple, How to divide the number of data1 by the number of data2?

data1:=[1, 2, 3];

data2:=[3, 4, 5];

in order to get something like this:

data3:=[0.333, 0.5, 0.6];

Upvotes: 3

Views: 634

Answers (2)

acer
acer

Reputation: 7271

In versions of Maple prior to "Maple 13" (2009) you can use the zip command:

data1 := [1, 2, 3]:

data2 := [3, 4, 5]:

zip(`/`, data1, data2);

          [1  1  3]
          [-, -, -]
          [3  2  5]

From Maple 13 onwards you can use the elementwise syntax,

data1 /~ data2;

          [1  1  3]
          [-, -, -]
          [3  2  5]

Notice that neither of those give you the floating-point approximations that you gave in your Question. Depending on how many digits you might want in a floating-point representation, you could use the evalf command:

T := evalf[10](data1 /~ data2):

T;

   [0.3333333333, 0.5000000000, 0.6000000000]

That can be further rounded to three digits,

evalf[3](T);

      [0.333, 0.500, 0.600]

You could also have only a smaller number of the (internally stored) floating-point digits be displayed.

interface(displayprecision=3):

T;

   [0.333, 0.500, 0.600]

# T is still stored to greater precision
lprint(T);
[.3333333333, .5000000000, .6000000000]

Upvotes: 1

Stef
Stef

Reputation: 15525

According to the documentation:

You can use operator /~.

data3 := data1 /~ data2

Disclaimer: I don't have maple on this computer to check, and I haven't used maple in many many years.

Bonus: For element-wise operators in other languages, you can find a comparison list on rosettacode:

Upvotes: 2

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