Reputation: 150
first of all hi,
Start Service
await AudioService.start(
backgroundTaskEntrypoint: _audioPlayerTaskEntrypoint,
params: {
'index': globalIndex,
'offline': offline,
'quality': preferredQuality
},
androidNotificationChannelName: 'BlackHole',
androidNotificationColor: 0xFF181818,
androidNotificationIcon: 'drawable/ic_stat_music_note',
androidEnableQueue: true,
androidStopForegroundOnPause: stopServiceOnPause,
);
await AudioService.updateQueue(globalQueue);
await AudioService.play();
Override Here the url part is added. But if I send request to the api for all elements, the performance will be bad.
@override
Future<void> onUpdateQueue(List<MediaItem> _queue) async {
await AudioServiceBackground.setQueue(_queue);
await AudioServiceBackground.setMediaItem(_queue[index!]);
concatenatingAudioSource = ConcatenatingAudioSource(
children: _queue
.map((item)
{
return AudioSource.uri(
Uri.parse(item.extras!['url'].toString()),
tag: item);
}
)
.toList(),
);
await _player.setAudioSource(concatenatingAudioSource);
await _player.seek(Duration.zero, index: index);
queue = _queue;
}
Instead, how can I make a request to the remote api and update the url without the item playing?
Here is something similar but I couldn't get it to work
How to fetch song details every time from an API before playing in just_audio and audio_service
Upvotes: 0
Views: 211
Reputation: 150
This is how I solved my problem.
@override
Future<void> onSkipToQueueItem(String mediaId) async {
final newIndex = queue.indexWhere((item) => item.id == mediaId);
if (newIndex == -1) return;
queue[newIndex].extras!['url'] = await SaavnAPI().get_mp3(queue[newIndex].extras!['url'].toString());
AudioServiceBackground.setMediaItem(queue[newIndex]);
_player.setUrl(queue[newIndex].extras!['url'].toString());
await AudioServiceBackground.setQueue(queue);
index = newIndex;
_player.seek(Duration.zero, index: newIndex);
if (!offline) addRecentlyPlayed(queue[newIndex]);
}
Upvotes: 0