CODEWITHSUNDEEP
c++stringnumberstostring
Meilianto Luffenz
Meilianto Luffenz

Reputation: 99

C++ Casting out a int into string

I am planning to change the elements inside the array of my x[] to cast out the number like 1, 2, 3, 4. But once i execute the code. it will show this error message.

error: no matching function for call to 
std::__cxx11::basic_string<char>::basic_string(int&)

Please anyone can help me to do anything to change my elements inside instead of using for loop? I can change it one by one by I want to change it all together just in case to save time and the amount of code written.

#include <iostream>

using namespace std;

string x[] = {"X", "O", "X", "O"};

int main()
{
    cout << x[0] + x[1] + x[2] + x[3] << endl;

    for (int i = 0; i < 4; i++){
        x[i] = (string)i;
    }

    cout << x[0] + x[1] + x[2] + x[3] << endl;

    return 0;
}

Upvotes: 1

Views: 206

Answers (1)

ΦXocę 웃 Пepe&#250;pa ツ
ΦXocę 웃 Пepe&#250;pa ツ

Reputation: 48258

this is the reason of the error:

x[i] = (string)i;

read here: how to use the function std::to_string so you can convert a number into a string

std::to_string(i);

#include <iostream>

std::string x[] = {"X", "O", "X", "O"};

int main()
{
    std::cout << "Before: " << x[0] + x[1] + x[2] + x[3] << std::endl;
    for (int i = 0; i < 4; i++)
    {
        x[i] = std::to_string(i);
    }
    std::cout << "after: " << x[0] + x[1] + x[2] + x[3] << std::endl;
 return 0;
}

here the example: https://ideone.com/X4dEdz

Upvotes: 2

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