CODEWITHSUNDEEP
r
climsaver
climsaver

Reputation: 617

Count the number of consecutive occurrences in a vector

I have the following vector:

vec <- c(28, 44, 45, 46, 47, 48, 61, 62, 70, 71, 82, 83, 104, 105, 111, 115, 125, 136, 137, 138, 146, 147, 158, 159, 160, 185, 186, 187, 188, 189, 190, 191, 192, 193, 209, 263, 264, 265, 266, 267, 268, 280, 283, 284, 308, 309, 318, 319, 324, 333, 334, 335, 347, 354)

Now I would like to get the number of consecutive occurrences in the vector of the minimum length two. So here this would be valid for the following cases:

44, 45, 46, 47, 48
61, 62
70, 71
82, 83
104, 105
136, 137, 138
146, 147
158, 159, 160
185, 186, 187, 188, 189, 190, 191, 192, 193
263, 264, 265, 266, 267, 268
283, 284
308, 309
318, 319
333, 334, 335

So there are 14 times cases of consecutive numbers, and I just need the integer 14 as output.

Anybody with an idea how to do that?

Upvotes: 3

Views: 440

Answers (4)

Ronak Shah
Ronak Shah

Reputation: 389355

Here's another base R one-liner using tapply -

sum(tapply(vec, cumsum(c(TRUE, diff(vec) != 1)), length) > 1)
#[1] 14

Upvotes: 1

R&#233;mi Coulaud
R&#233;mi Coulaud

Reputation: 1714

Brut force :

var <- sort(var)
nconsecutive <- 0
p <- length(var)-1
for (i in 1:p){
    if((var[i + 1] - var[i]) == 1){
        consecutive <- consecutive + 1
    }else{
        # If at least one consecutive number
        if(consecutive > 0){
        # when no more consecutive numbers add one to your increment
            nconsecutive = nconsecutive + 1
        }
        # Re set to 0 your increment
        consecutive <- 0
    }
}

Upvotes: 1

Basti
Basti

Reputation: 1773

We can use rle and diff functions :

a=rle(diff(vec))
sum(a$values==1)

Upvotes: 6

Kra.P
Kra.P

Reputation: 15153

diff and split will help

vec2 <- split(vec, cumsum(c(1, diff(vec) != 1)))
vec2[(sapply(vec2, function(x) length(x))>1)]

$`2`
[1] 44 45 46 47 48

$`3`
[1] 61 62

$`4`
[1] 70 71

$`5`
[1] 82 83

$`6`
[1] 104 105

$`10`
[1] 136 137 138

$`11`
[1] 146 147

$`12`
[1] 158 159 160

$`13`
[1] 185 186 187 188 189 190 191 192 193

$`15`
[1] 263 264 265 266 267 268

$`17`
[1] 283 284

$`18`
[1] 308 309

$`19`
[1] 318 319

$`21`
[1] 333 334 335

Upvotes: 2

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