CODEWITHSUNDEEP
php
Sumit Thakur
Sumit Thakur

Reputation: 3

Getting strange output of below code. I need explaination how it wil calculate output

<?php
$test = 'text1';
$test["02"] = "Hello";

var_dump($test);

Output is:: string(5) "teHt1"

Upvotes: 0

Views: 207

Answers (2)

Aishwarya m k
Aishwarya m k

Reputation: 36

in the first line $test stored the value as 'text1' start giving offset value for the string from left to right from 0 to (stringlength-1) and each character byte size in string will occupies one byte of memory.

ie,

...

$test[0] =>'t';
$test[1] =>'e';
$test[2]=>'x';
$test[3]=>'t';
$test[4]=> '1';

...

so, $test[2] current value as 'x' but we are tried to override in the line $test["02"] = "Hello"; but its memory size just one byte so it stored only 'H' from the string in 'Hello'

that's why when you dump the variable $test value is now "teHt1";

Upvotes: 2

tahabas
tahabas

Reputation: 89

Strings are not arrays even you can use bracket notation.you are trying to replace second byte offset of the $test variable.So it takes the first byte offset from "Hello" and replaces x with H.

Upvotes: 0

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