Reputation: 97
Original XML amp; is added by JAXB which need to be ignore :-
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<emp>
<address>7 stret & new </address>
<name>Naveenqq</name>
</emp>
expected without amp;(actual value want) :
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<emp>
<address>7 stret & new </address>
<name>Naveenqq</name>
</emp>
I have tried below code:
private static void jaxbObjectToXML(Emp employee) throws IOException, SAXException, ParserConfigurationException
{
try
{
JAXBContext jaxbContext = JAXBContext.newInstance(Emp.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
//jaxbMarshaller.setProperty("jaxb.encoding", "US-ASCII");
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
//jaxbMarshaller.setProperty(OutputKeys.ENCODING, "ASCII");
//jaxbMarshaller.setProperty(CharacterEscapeHandler.class.getName(), new CustomCharacterEscapeHandler());
// jaxbMarshaller.setProperty(CharacterEscapeHandler.class.getName(), new CharacterEscapeHandler() {
//
// @Override
// public void escape(char[] ch, int start, int length, boolean isAttVal, Writer out) throws IOException {
// out.write( ch, start, length );
//
// }
// });
//
// StringWriter writer = new StringWriter();
File file = new File("employee1.xml");
jaxbMarshaller.marshal(employee, file);
//
// DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
// DocumentBuilder builder = factory.newDocumentBuilder();
// InputSource is = new InputSource( new StringReader( writer.toString() ) );
// Document doc = builder.parse( is );
System.out.println("done::");
}
catch (JAXBException e)
{
e.printStackTrace();
}
}
Please help how to resolve same , I have tried all encoding type
Upvotes: 0
Views: 630
Reputation: 3540
The problem is that &
in the XML is not valid and if you try to validate an XML with &
it would fail. JAXB
is pretty intelligent so it tries to replace the special characters with their character entities. A similar thing happens in HTML as well. You can refer here.
But if you observe the values after JAXB Unmarshalling
it has been replaced by &
instead of &
. So you do not have to worry about it having in the XML. I guess if you take the route which you want then it would lead to many complications and your XML itself will be invalid.
XML:
<emp>
<address>7 stret & new</address>
<name>Naveenqq</name>
</emp>
Root:
@Data
@XmlRootElement(name = "emp")
@XmlAccessorType(XmlAccessType.FIELD)
public class Root {
private String address;
private String name;
}
Main:
public class Main {
public static void main(String[] args) throws JAXBException, XMLStreamException {
final InputStream inputStream = Main.class.getClassLoader().getResourceAsStream("test.xml");
final XMLStreamReader xmlStreamReader = XMLInputFactory.newInstance().createXMLStreamReader(inputStream);
final Unmarshaller unmarshaller = JAXBContext.newInstance(Root.class).createUnmarshaller();
final Root root = unmarshaller.unmarshal(xmlStreamReader, Root.class).getValue();
System.out.println(root.toString());
Marshaller marshaller = JAXBContext.newInstance(Root.class).createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(Marshaller.JAXB_ENCODING, "US-ASCII");
//marshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders", new XmlCharacterHandler());
marshaller.marshal(root, System.out);
}
}
Output:
Root(address=7 stret & new, name=Naveenqq)
<?xml version="1.0" encoding="US-ASCII"?>
<emp>
<address>7 stret & new</address>
<name>Naveenqq</name>
</emp>
As you can see in the output Root(address=7 stret & new, name=Naveenqq)
it has been replaced by &
so you can continue to use the same.
Hope the explanation helps.
Upvotes: 2
Reputation: 163615
Your expected value is not valid XML, so there's no way you can persuade any XML-aware tool to generate it.
Why are you trying to generate invalid XML?
Upvotes: 1