CODEWITHSUNDEEP
awk
Leo
Leo

Reputation: 1919

using AWK, how do I convert a decimal number to hexadecimal

If I do have an input stream of decimal numbers, e.g.

100 2000 599 232

and I pass them to awk, how do I print them in Hexadecimal notation?.

for example

0x64 0x74D 0x257 0xE8

starting script ...

echo "100 2000 599 232" | awk '{ print $1 }' #here print in hexa instead of decimal

Upvotes: 2

Views: 945

Answers (2)

RARE Kpop Manifesto
RARE Kpop Manifesto

Reputation: 2805

quick caveat - mawk 1.3.4 has severe limitations when it comes to printing octal and hex codes :

$ gawk  'BEGIN{ printf("%\043.16x\n",8^8*-1-2) }'
0xfffffffffefffffe

$ nawk  'BEGIN{ printf("%\043.16x\n",8^8*-1-2) }'
0xfffffffffefffffe

$ mawk  'BEGIN{ printf("%\043.16x\n",8^8*-1-2) }'
0000000000000000

$ mawk2 'BEGIN{ printf("%\043.16x\n",8^8*-1-2) }'
0xfffffffffefffffe

It's not even that large a value (-16777218), and mawk 1.3.4 completely bellyflops. On the flip side, it can directly decipher some hex constants (only gawk not in either posix or traditional mode can directly decipher octal constants :

$ mawk  'BEGIN { OFMT="%.f"; print +"0xDEADBEEF" }'
3735928559

nawk  'BEGIN { OFMT="%.f"; print +"0xDEADBEEF" }'
3735928559

$ mawk2  'BEGIN { OFMT="%.f"; print +"0xDEADBEEF" }'
0

$ gawk --posix 'BEGIN{ OFMT="%.f"; print +"0xDEADBEEF" }'
3735928559 <====  note the difference - posix mode only can decipher strings
                  the "+" in front is also necessary cuz gawk will just print
                  it as a string otherwise.

$ gawk -e 'BEGIN { OFMT="%.f"; print 0xDEADBEEF }'
3735928559 <==== standard mode only can decipher clear text ones

 - mawk2 is the only one among those above that 
   even prints anything out with %p in printf(), 
   but still erroring out, as such

  mawk2: line 1: invalid control character 'p'
  in [s]printf format ("0x10f0099da

 - both gawk and nawk properly prints out %a

Upvotes: 0

Chris Dodd
Chris Dodd

Reputation: 126203

You can use printf in awk with a format string to convert to hex:

awk '{ printf "%x\n", $1 }'

Upvotes: 4

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