CODEWITHSUNDEEP
javascriptsorting
Shogun
Shogun

Reputation: 13

Sort an array of objects based on key/value of array

I need to sort an array of objects. How can I sort this array based on key arrval[index]?

arr = [
  { id: 0, name: 'Name 1', arrval: [5, 3, 1] },
  { id: 1, name: 'Name 2', arrval: [6, 4, 3] },
  { id: 2, name: 'Name 3', arrval: [3, 2, 0] },
]

So if I want to sort it by arrval[1], ascending, the result should be:

arr = [
  { id: 2, name: 'Name 3', arrval: [3, 2, 0] },
  { id: 0, name: 'Name 1', arrval: [5, 3, 1] },
  { id: 1, name: 'Name 2', arrval: [6, 4, 3] },
]

I can already sort this if I sort it by id or name but I can't seem to make it work by arrval

Upvotes: 1

Views: 76

Answers (5)

trincot
trincot

Reputation: 350272

The accepted answer sorts by the first array value. If you need to be able to deal with ties, where then the second array value becomes decisive, ...etc, then use this:

    
const src = [
  { id: 0, name: 'Name 1', arrval: [5, 3, 3] },
  { id: 1, name: 'Name 2', arrval: [5, 3, 1] },
  { id: 2, name: 'Name 3', arrval: [5, 2, 0, 1] },
  { id: 3, name: 'Name 4', arrval: [5, 2, 0] },
]

src.sort(({arrval: a}, {arrval: b}) => {
    for (let i = 0, len = Math.min(a.length, b.length); i < len; i++) {
        if (a[i] !== b[i]) return a[i] - b[i];
    }
    return a.length - b.length;
});

console.log(src);

Upvotes: 0

Yevhen Horbunkov
Yevhen Horbunkov

Reputation: 15530

Simple as that

const src = [
  { id: 0, name: 'Name 1', arrval: [5, 3, 1] },
  { id: 1, name: 'Name 2', arrval: [6, 4, 3] },
  { id: 2, name: 'Name 3', arrval: [3, 2, 0] },
]

const sortByKeyIdx = ([...arr], key, idx) =>
  arr
    .sort(({[key]:a}, {[key]:b}) => 
      a[idx]-b[idx])
    
console.log(sortByKeyIdx(src, 'arrval', 1))

Upvotes: 1

user15889308
user15889308

Reputation:

There is two way to do this

first:

let arr = [{
    id: 0,
    name: 'Name 1',
    arrval: [5, 3, 1]
  },
  {
    id: 1,
    name: 'Name 2',
    arrval: [6, 4, 3]
  },
  {
    id: 2,
    name: 'Name 3',
    arrval: [3, 2, 0]
  },
]
let index = 1
arr.sort((a, b) => {
  if (a.arrval[index] < b.arrval[index]) return -1
  else if (a.arrval[index] < b.arrval[index]) return 1
  else return 0
})

console.log(arr)

second:

let arr = [{
    id: 0,
    name: 'Name 1',
    arrval: [5, 3, 1]
  },
  {
    id: 1,
    name: 'Name 2',
    arrval: [6, 4, 3]
  },
  {
    id: 2,
    name: 'Name 3',
    arrval: [3, 2, 0]
  },
]
let index = 1
arr.sort((a, b) => a.arrval[1] - b.arrval[1])

console.log(arr)

Upvotes: 0

Karma Blackshaw
Karma Blackshaw

Reputation: 942

Just pass the arrval index and sort it like you normally would. You can try this solution:

const sort = index => {
  const arr = [
    { id: 0, name: 'Name 1', arrval: [5, 3, 1] },
    { id: 1, name: 'Name 2', arrval: [6, 4, 3] },
    { id: 2, name: 'Name 3', arrval: [3, 2, 0] }
  ]

  return arr.sort((x, y) => x.arrval[index] - y.arrval[index])
}

console.log(sort(2))

Upvotes: 0

Фарид Ахмедов
Фарид Ахмедов

Reputation: 902

Just sort by arrval like you sort by id or name

arr.sort( (a, b) => a.arrval[0] - b.arrval[0] )

Upvotes: 0

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