CODEWITHSUNDEEP
python
HUNG JOE KIT
HUNG JOE KIT

Reputation: 11

How to apply type check?

My task is to write a function named only_ints that takes two parameters. Your function should return True if both parameters are integers, and False otherwise.

For example, calling only_ints(1, 2) should return True, while calling only_ints("a", 1) should return False.

I'm confused. How do I apply type()? Because isinstance(False, int) outputs --> True

Upvotes: 0

Views: 1054

Answers (3)

alparslan mimaroğlu
alparslan mimaroğlu

Reputation: 1480

You can use type and ==. isinstance sadly does not behave intuitively in this situation.

def only_ints(x,y):
    return type(x) == int and type(y) == int

Upvotes: 0

Bill the Lizard
Bill the Lizard

Reputation: 405735

You could use == to compare the type of a variable or value to a known type.

>>> type(True) == int
False
>>> type(3) == int
True

Before you implement only_ints using type, you should verify that you don't want True and False to be considered int. Booleans do evaluate to integer values in Python in many contexts.

Upvotes: 0

balderman
balderman

Reputation: 23815

isinstance is the right tool to be used here. bool is a private case of int and therefore we give him a special care :-)

Try (print(True + 1)) and see that the result is 2

def only_ints(x: int, y:int) -> bool:
    return isinstance(x, int) and not isinstance(x, bool) and isinstance(y, int) and not isinstance(y, bool)

print(only_ints(4, 6))
print(only_ints(4, False))

output

True
False

Upvotes: 1

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