CODEWITHSUNDEEP
pythonpython-3.xpathlib
John
John

Reputation: 2922

How can you prefix a Python pathlib.Path with another path?

I have a pathlib.Path('/etc'). If I need to prefix it with pathlib.Path('/mnt/chroot') and do something like:

Path('/mnt/chroot') / Path('/etc')

I just end up with: PosixPath('/etc'), presumably because both Path's are absolute paths, and can't be concatenated.

I can hack together a solution with something like:

Path('/mnt/chroot') / str(Path('/etc')).removeprefix('/')

But that is long-winded, and hackish. Is there a simpler, proper way to do this?

Upvotes: 3

Views: 2326

Answers (2)

Quber
Quber

Reputation: 79

I just want to expand on Kyle's answer with a cross platform solution. It dynamically gets the root of the filesystem.

root = os.path.abspath(".").split(os.path.sep)[0] + os.path.sep
path = Path("/mnt/chroot") / Path("/etc").relative_to(root)

Do not know if this adds anything but here it is.

Upvotes: 1

Kyle Parsons
Kyle Parsons

Reputation: 1525

You can turn Path('/etc') into a relative path with the relative_to method:

Path('/mnt/chroot') / Path('/etc').relative_to('/')

Upvotes: 7

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