CODEWITHSUNDEEP
csignals
Kinnturo
Kinnturo

Reputation: 141

SIGUSR1 Signal is not triggering

I'm starting to learn signals and how to trigger them. I have this simple code that triggers a signal using SIGUSR1, but when I run the code, the only thing that gets printed is the "Starting..." line. Nothing else gets printed. Am I doing something wrong?

#include <signal.h>
#include <stdio.h>

void my_handler(int signum)
{
    printf("Hello\n");
    printf("%d\n", signum);
    if (signum == SIGUSR1) {
        printf("Receveid\n");
    }
}

int main() {
    printf("Starting...\n");
    signal(SIGUSR1, my_handler);
    return 0;
}

Upvotes: 0

Views: 1007

Answers (1)

Oka
Oka

Reputation: 26375

signal only registers a signal handler - the function to be called when the process receives a signal. From within your program, you can use raise to send a signal to the calling process.

If you are in a POSIX environment, you should take a look at man 7 signal-safety for a list of functions that are safe to call from within signal handlers (additional information in this answer). printf is not included in this list - nor are a lot standard library functions. Its better to use an operation which is atomic with regards to signals, such as write (or reentrant, such as strlen).

A cursory example of using raise, which returns 0 on success, and nonzero on error.

#include <signal.h>
#include <stdio.h>
#include <string.h>
#include <unistd.h>

void my_handler(int signum) {
    char msg[] = "SIGUSR1 handler\n";

    if (signum == SIGUSR1)
        write(STDOUT_FILENO, msg, strlen(msg));
}

int main(void) {
    printf("Starting...\n");

    signal(SIGUSR1, my_handler);

    (void) getchar();

    if (raise(SIGUSR1) != 0)
        fprintf(stderr, "Could not raise signal.\n");
}

Upvotes: 2

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