CODEWITHSUNDEEP
pythonfrequency
victorialangoe
victorialangoe

Reputation: 57

Count word frequency without using count()

Python counts every character, but not word. Something to do to change? Not using count()

dict = {}
def convert(sentence):
    return (sentence.split())
 

sentece =  input("write something: ")
print( convert(sentence))


for item in sentence:
    if item not in ordbok:
        dict[item] = 0
    dict[item] += 1
print(dict)

Upvotes: 0

Views: 245

Answers (3)

Navaneeth Sen
Navaneeth Sen

Reputation: 6466

Please find below the issues with your current logic:

  • iterate on the return list you get after convert(sentence).

  • if you iterate on the sentence, it will take character count

Please find the code below with the corrections:

dict = {}

def convert(sentence):
    return (sentence.split())

sentence = input("write something: ")
print(convert(sentence))

for item in convert(sentence):
    if item not in dict:
        dict[item] = 0
    dict[item] += 1
print(dict)

Upvotes: 1

I'mahdi
I'mahdi

Reputation: 24049

You can use collections.Counter like below:

from collections import Counter
Counter(convert(sentence))

Your Whole code:

def convert(sentence):
    return (sentence.split())
 
sentece =  input("write something: ")

from collections import Counter
dct = Counter(convert(sentence))

Output:

write something: victorialangoe victorialangoe

Counter({'victorialangoe': 2})

Upvotes: 1

Niel Godfrey P. Ponciano
Niel Godfrey P. Ponciano

Reputation: 10699

You can easily count anything with collections.Counter.

from collections import Counter

word_count = Counter(sentence.casefold().split())

Here, word_count would be a dictionary containing all words in the sentence and their respective counts.

Upvotes: 2

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