Reputation: 6105
I see { } are used for closures, and then I believe when a $ is put in front of braces, it is simply doing a variable substitution within a string. I can't find the documentation on how the $ works in the reference ... hard to search on it unfortunately, and the Groovy String documentation is lacking in introducing this. Can you please point me to the documentation and/or explain the "$" operator in Groovy -- how all it can be used? Does Grails extend it at all beyond Groovy?
Upvotes: 60
Views: 122202
Reputation: 463
Work in side Jenkins File in pipeline
#!/usr/bin/env groovy
node{
stage ('print'){
def DestPath="D\$\\"
println("DestPath:${DestPath}")
}
}
Upvotes: 1
Reputation: 39570
$
is not an operator in Groovy. In string substitution it identifies variables within the string - there's no magic there. It's a common format used for inline variables in many template and programming languages.
All special Groovy operators are listed here: http://groovy-lang.org/operators.html
Upvotes: 12
Reputation: 14197
In a GString (groovy string), any valid Groovy expression can be enclosed in the ${...} including method calls etc.
This is detailed in the following page.
Upvotes: 65
Reputation: 187529
Grails does not extend the usage of $ beyond Groovy. Here are two practical usages of $
Within a GString you can use $ without {} to evaluate a property path, e.g.
def date = new Date()
println "The time is $date.time"
If you want to evaluate an expression which is more complex than a property path, you must use ${}, e.g.
println "The time is ${new Date().getTime()}"
Dynamically accessing a property
def prop = "time"
new Date()."$prop"
Dynamically invoking a method
def prop = "toString"
new Date()."$prop"()
As pointed out in the comments this is really just a special case of string interpolation, because the following is also valid
new Date().'toString'()
Upvotes: 53