CODEWITHSUNDEEP
haskellparse-error
Magnus
Magnus

Reputation: 1

Why do I get parse error after my if then else statement in Haskell?

Im getting parse error on my if then else statement and I dont understand why. I have checked the functions, and as far as I can tell all of them are getting the arguments they need, so I dont understand why this is happening. Im very new to haskell so help in understanding this would be deeply appreciated.

replace :: [(Int,Int)] -> String -> String
replace xs ys = if translate (manipulator (fst (convert xs)) (snd (convert xs)) ys) /= ""
then take (fst (convert xs)) ys ++ (manipulator (fst (convert xs)) (snd (convert xs)) ys) ++ drop (snd (convert xs)) ys
else take (fst (convert xs)) ys ++ stjerner (snd (convert xs) - fst (convert xs)) ++ drop (snd (convert (xs)) ys

--get parse error here, see picture.
stjerner :: Int -> String
stjerner 0 = ""
stjerner int | int > 0 =  "*" ++ stjerner (int -1)
manipulator:: Int -> Int -> String -> String
manipulator low high xs = take high (drop low xs)
convert :: [a] -> a
convert [a] = a

picture of parse error here

Upvotes: 0

Views: 148

Answers (1)

jacobm
jacobm

Reputation: 14025

The last expression in you else clause --- drop (snd (convert (xs)) ys -- is misparenthesized. You've got 3 open parens but only 2 close parens. I think you meant drop (snd (convert xs)) ys.

Upvotes: 1

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