Reputation: 1
I am trying to sort orders in descending and start after on particular key but its not working
nextAfter : -Mk4-n5BnVpwhum62n2g or any Key / _id
db record:
{
'-Mk4-n5BnVpwhum62n2g': {
_id: '-Mk4-n5BnVpwhum62n2g',
createdAt: -1632171667626,
name: 'abc'
},
'-Mk40Ko9DbSeMdjIpY4': {
_id: '-Mk40Ko9DbSeMdjIpY4',
createdAt: -1632171809831,
name: 'new '
}
}
trying query :
query = dbRef.orderByChild('createdAt').startAfter(nextAfter).limitToFirst(limit);
Upvotes: 0
Views: 618
Reputation: 26171
The startAfter()
method accepts two parameters - the first is the relevant orderBy
value and the second is the optional key of the last entry (for when multiple entries have the same value for the orderBy
criteria). So to correctly paginate the reference, you need to pass the previous entry's createdAt
value and its key.
const baseQuery = dbRef
.orderByChild('createdAt')
.limitToFirst(limit);
let pageCount = 0, lastChildOnPage = undefined;
const children = [];
while (true) {
const pageQuery = pageCount === 0
? baseQuery
: baseQuery
.startAfter(lastChildOnPage.createdAt, lastChildOnPage.key);
const pageSnapshot = await pageQuery.once('value');
pageSnapshot.forEach((childSnapshot) => {
children.push({ key: childSnapshot.key, ...childSnapshot.val() });
})
const newLastChildOnPage = children[children.length-1];
if (lastChildOnPage !== newLastChildOnPage) {
lastChildOnPage = newLastChildOnPage;
pageCount++;
} else {
break; // no more data
}
}
console.log(`Grabbed ${pageCount} page(s) of data, retrieving ${children.length} children`);
Upvotes: 3