CODEWITHSUNDEEP
pythonlistfor-loopwhile-loopnumbers
전수환
전수환

Reputation: 29

Create an odd number list

i want to make an odd number list by using 'while' and 'for'

a = []
x = 1
while x < 101:
    if x % 2 != 0:
        a.append(x)
        x = x + 1
print(a)

but nothing happened... and other unrelated codes which is in another sentence are also not executed. what is my problem?

Upvotes: 2

Views: 949

Answers (4)

Ayyoub ESSADEQ
Ayyoub ESSADEQ

Reputation: 788

odd = [i for i in range(101) if i%2 != 0]
print(odd)

Upvotes: 0

Bhagyesh Dudhediya
Bhagyesh Dudhediya

Reputation: 1856

You can use the range function as well (for for loop) which handles the increment part in the loop as below:
FOR LOOP:

odd=[]
for i in range(101):
    if (i%2!=0):
        odd.append(i)
print (odd)

WHILE LOOP:

odd=[]
i = 1
while i<101:
    if i%2 != 0:
        odd.append(i)
    i+=1
print (odd)

Upvotes: 0

Sravan JS
Sravan JS

Reputation: 161

When you increment x, it should be out of 'if' condition. increment should happen under while

a = list()
x = 1
while x <101:
    if x%2 != 0:
        a.append(x)
    x += 1
print(a)

Upvotes: 0

Gilad Green
Gilad Green

Reputation: 37299

You should increase the value of x in each iteration and not only if the value is an odd number:

a = []
x = 1
while x < 101:
    if x % 2 != 0:
        a.append(x)
    x += 1
print(a)

Though this is probably for learning purposes note that you could achieve this using the range function as follows: list(range(1,101, 2)).

Upvotes: 4

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