How to find similarity between mySQL rows?

Question

I am trying to create a script that finds a matching percentage between my table rows. For example my mySQL database in the table products contains the field name (indexed, FULLTEXT) with values like

LG 50PK350 PLASMA TV 50" Plasma TV Full HD 600Hz 
LG TV 50PK350 PLASMA 50"
LG S24AW 24000 BTU
Aircondition LG S24AW 24000 BTU Inverter

As you may see all of them have some same keyword. But the 1st name and 2nd name are more similar. Additionally, 3rd and 4th have more similar keywords between them than 1st and 2nd.

My mySQL DB has thousands of product names. What I want is to find those names that have more than a percentage (let's say 60%) of similarity.

For example, as I said, 1st, 2nd (and any other name) that match between them with more than 60%, will be echoed in a group-style-format to let me know that those products are similar. 3rd and 4th and any other with more than 60% matching will be echoed after in another group, telling me that those products match.

If it is possible, it would be great to echo the keywords that satisfy all the grouped matching names. For example LG S24AW 24000 BTU is the keyword that is contained in 3rd and 4th name.

At the end I will create a list of all those keywords.

What I have now is the following query (as Jitamaro suggested)

Select t1.name, t2.name From products t1, products t2

that creates a new name field next to all other names. Excuse me that I don't know how to explain it right but this is what it does: (The real values are product names like above)

Before the query

-name-
A
B
C
D
E

After the query

-name- -name-
A        A
B        A
C        A
D        A
E        A
A        B
B        B
C        B
D        B
E        B
.
.
.

Is there a way either with mySQL or PHP that will find me the matching names and extract the keywords as I described above? Please share code examples.

Thank you community.

Answer 1

Query the DB with LIKE OR REGEXP:

SELECT * FROM product WHERE product_name LIKE '%LG%';
SELECT * FROM product WHERE product_name REGEXP "LG";

Loop the results and use similar_text():

$a = "LG 50PK350 PLASMA TV 50\" Plasma TV Full HD 600Hz"; // DB value
$b = "LG TV 50PK350 PLASMA 50\"" ; // USER QUERY

$i = similar_text($a, $b, $p);
echo("Matched: $i  Percentage: $p%");

//outputs: Matched: 21 Percentage: 58.3333333333%

Your second example matches 62.0689655172%:

$a = "LG S24AW 24000 BTU"; // DB value
$b = "Aircondition LG S24AW 24000 BTU Inverter" ; // USER QUERY

$i = similar_text($a, $b, $p);
echo("Matched: $i  Percentage: $p%");

You can define a percentage higher than, lets say, 40%, to match products.
Please note that similar_text() is case SensItivE so you should lower case the string.

Answer 2

This question is similar :) to this one:

What is the best way to implement a substring search in SQL?

Trigram can easily find similar rows, and in that question i posted a php+mysql+trigram solution.

Answer 3

This is a clustering problem, which can be resolved by a data mining method. ( http://en.wikipedia.org/wiki/Cluster_analysis) It requires a lot of memory and computation intensive operations which is not suitable for database engine. Otherwise, separate data mining, text mining, or business analytics software wouldn't have existed.

Answer 4

It seems that you might always want to return the shortest string?? That's more or a question than anything. But then you might have something like...

SELECT * FROM products LIMIT 1
WHERE product_name like '%LG%'
ORDER BY LENGTH(product_name) ASC

Answer 5

I`d advise you to use some fulltext search engine, like sphinx. It has possibilities to implement any algorithm you want. For example, you may use "quorom" or "any" searches.

Answer 6

If your database simply had a UPC code as one of it's fields, and this field was well-maintained, i.e., you could trust that it was entered correctly by the database maintainer and correctly reflected what the item was -- then you wouldn't need to do all of the work you suggest.

An even better idea might be to have a UPC field in your next database -- and constrain it as unique.

Database users attempt to put an-already-existing UPC into the database -- they get an error.

Database maintains its integrity.

And if such a database maintained its integrity -- the necessity of doing what you suggest never arises.

This probably doesn't help much with your current task (apologies) -- but for a future similar database -- you might wish to think about it...

Answer 7

It sounds like you've gone through all this trouble to explain a complex scenario, then said that you want to ignore the optimal answers and just get us to give you the "handshake" protocol (everything is compared to everything that hasn't been compared to it yet). So... pseudocode:

select * from table order by id
while (result) {
    select * from table where id > result_id
}

That will do it.

Answer 8

If you want to check all names against each other you need a cross join in mysql. There are many ways to achieve this:

1. Select a, b From t1, t2

2. Select a, b From t1 Join t2

3. Select a, b From t1 Cross Join t2

Then you can loop through the result. This is the same when I say create a 2d array with n^2-(n-1) elements and each element is connected with each other.

P.S.: Select t1.name, t2.name From products t1, products t2

Answer 9

Ok, I think I was trying to implement very much similar thing. It can work the same as the google chrome address box. When you type the address it gives you the suggestions. This is what you are trying to achieve as far I am concerned.

I cannot give you exact solution to that but some advice.

1. You need to implement the dropdown box where someone starts to enter the product they are looking for
2. Then you need to get the current value of the dropdown and then run query like guy posted above. Can be "SELECT * FROM product WHERE product_name LIKE 'LG%';"
3. Save results of the query
4. Refresh the page
5. Add the results of the query to the dropdown

Note:

You need to save the query results somewhere like the text file with the HTML code i.e. "option" LG TS 600"/option" (add <> brackets to option of course). This values will be used for populating your option box after the page refresh. You need to set up the users session for the user to get the same results for the same user, otherwise if more users would use the search at the same time it could clash. So, with the search id and session id you can match them then. You can save it in the file or the table. Table would be more convenient. It is actually in my sense the whole subsystem for that what are you looking for.

I hope it helps.

Answer 10

When I look at your examples, I consider how I would try to find similar products based on the title. From your two examples, I can see one thing in each line that stands out above anything else: the model numbers. 50PK350 probably doesn't show up anywhere other than as related to this one model.

Now, MySQL itself isn't designed to deal with questions like this, but some bolt-on tools above it are. Part of the problem is that querying across all those fields in all positions is expensive. You really want to split it up a certain way and index that. The similarity class of Lucene will grant a high score to words that rarely appear across all data, but do appear as a high percentage of your data. See High level explanation of Similarity Class for Lucene?

You should also look at Comparison of full text search engine - Lucene, Sphinx, Postgresql, MySQL?

Scoring each word against the Lucene similarity class ought to be faster and more reliable. The sum of your scores should give you the most related products. For the TV, I'd expect to see exact matches first, then some others of the same size, then brand, then TVs in general, etc.

Whatever you do, realize that unless you alter the data structures by using another tool on top of the SQL system to create better data structures, your queries will be too slow and expensive. I think Lucene is probably the way to go. Sphinx or other options not mentioned may also be up for consideration.

Answer 11

One possible solution is to use Damerau-Levenstein distance. It could be used like this

select *
from products p
where DamerauLevenstein(p.name, '*user input here*')<=*X*

You'll have to figure out X that suites your needs best. It should be integer greater than zero. You could have it hard-coded, parameterized or calculated as needed.

The trickiest thing here is DamerauLevenstein. It has to be stored procedure, that implements Damerau-Levenstein algorithm. I don't have MySQL here, so I might write it for you later this day.

Update: MySQL does not support arrays in stored procedures, so there is no way to implement Damerau-Levenstein in MySQL, except using temporary table for each function call. And that will result in terrible performance. So you have two options: loop through the results in PHP with levenstein like Alix Axel suggests, or migrate your database to PostgreSQL, where arrays are supported. There is also an option to create User-Defined function, but this requires writing this function in C, linking it to MySQL and possibly rebuilding MySQL, so this way you'll just add more headache.

Answer 12

Maybe you want to find the longest common substring from the 2 strings? Then you need to compute a suffix tree for each of your strings see here http://en.wikipedia.org/wiki/Longest_common_substring_problem.

Answer 13

Here is another idea (but I'm voting for levenshtein()):

Create a temporary table of all words used in names and their frequencies.

Choose range of results (most popular words are probably words like LCD or LED, most unique words could be good, they might be product actual names).

Suggest for each of result words either:

• results with those words
• results containing longest substring (like this: http://forums.mysql.com/read.php?10,277997,278020#msg-278020 ) of those words.

Answer 14

This is trickier than it seems and there is information missing in your post:

• How are people going to use this auto-complete function?
• Is it relevant that you can find all names for a product? Because apparently not all stores name their products similarly so a clerk might not be able to find the product (s)he found.
• Do you have information about which product names are for the same product?
• Is it relevant from which store you're searching? where is this auto-complete used?
• Should the auto-complete really only suggest products that match all the words you typed? (it's not so hard, technically, to correct typos)

I think you need a more clear picture of what you (or better yet: the users) want this auto-complete function to do.

An auto-complete function is very much a user-friendly type feature. It aids the user, possibly in a fuzzy way so there is no single right answer. You have to figure out what works best, not what is easiest to do technically.

First figure out what you want, then worry about technology.

Answer 15

As for your second question, the levenshtein() function (in MySQL) would be a good candidate.

Answer 16

Your approach seems sound. For matching similar products, I would suggest a trigram search. There's a pretty decent explanation of how this works along with the String::Trigram Perl module.

I would suggest using trigram search to get a list of matches, perhaps coupled with some manual review depending on how much data you have to deal with and how frequent you need to add new products. I've found this approach to work quite well in practice.

Answer 17

You can use LIKE to find similar product names within the table. For example:

SELECT * FROM product WHERE product_name LIKE 'LG%';