CODEWITHSUNDEEP
javascriptarraysloopsbackend
user16834070
user16834070

Reputation: 13

Iterating over an array and appending its values to a dictionary in javascript

I am trying to iterate over an dictionary that has values in form of array those values I want to put in a dictionary I am confused as to what should I do to obtain this

Here is the data that I want to iterate over :

{
t: ["20181019,20181022,...."],
o: ["180.34,189.45,..."],
h: ["180.99,181.40,..."],
l: ["178.57,177.56,...."],
c: ["179.85 ,178.75,...."]
}

Here is what the end product should look like :

[
    { time: '20181019', open: 180.34, high: 180.99, low: 178.57, close: 179.85 },
    { time: '20181022', open: 180.82, high: 181.40, low: 177.56, close: 178.75 },
    { time: '20190509', open: 193.31, high: 195.08, low: 191.59, close: 194.58 },
]

Upvotes: 0

Views: 993

Answers (3)

Ganesan C
Ganesan C

Reputation: 277

Try below code.

var data = {
  t: ["20181019,20181022"],
  o: ["180.34,189.45"],
  h: ["180.99,181.40"],
  l: ["178.57,177.56"],
  c: ["179.85 ,178.75"]
}

var res = [];

const open = data.o.toString().split(",");
const high = data.h.toString().split(",");
const low = data.l.toString().split(",");
const close = data.c.toString().split(",");

data.t.toString().split(",").forEach((item, index) => {
  res.push({
    time : item,
    open : open[index],
    high: high[index],
    low: low[index],
    close: close[index]
  });
})

console.log(res);

Upvotes: 0

Faruk
Faruk

Reputation: 444

Here is the quick solution:

const data = {
  t: ['20181019,20181022,....'],
  o: ['180.34,189.45,...'],
  h: ['180.99,181.40,...'],
  l: ['178.57,177.56,....'],
  c: ['179.85 ,178.75,....'],
};

let prepared = {};
Object.keys(data).map((key) => {
  prepared[key] = data[key][0].split(',');
});

const res = prepared.t.map((tVal, index) => {
  return {
    time: tVal,
    open: prepared.o[index],
    high: prepared.h[index],
    low: prepared.l[index],
    close: prepared.c[index],
  };
});

console.log(res);

Upvotes: 1

DecPK
DecPK

Reputation: 25408

You can easily achieve the result using Object.keys, reduce

const obj = {
  t: ["20181019,20181022"],
  o: ["180.34,189.45"],
  h: ["180.99,181.40"],
  l: ["178.57,177.56"],
  c: ["179.85 ,178.75"],
};

const dict = { t: "time", o: "open", h: "high", l: "low", c: "close" };

const tempObj = Object.keys(obj).forEach((k) => (obj[k] = obj[k][0].split(",")));

const result = Array.from({ length: obj.t.length }, (_, i) => {
  return Object.entries(obj).reduce((acc, [k, v]) => {
        acc[dict[k]] = k === "t" ? v[i] : +v[i];
    return acc;
  }, {});
});

console.log(result);
/* This is not a part of answer. It is just to give the output fill height. So IGNORE IT */
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

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