Reputation: 33
I created a database to store a menu informations with 3 level (2 sub menus level). You can see it on the left here : https://volt-services.fr/sites/stge/index.php#
Here is the table in the database:
And the code to translate it to HTML:
<?php
$req = $DB->query("SELECT * FROM menu ORDER BY ordered");
foreach ($req as $r) {
if($r->level == 1) {
$tab[$r->ordered] = array($r->id,$r->name,$r->class,$r->icon);
} elseif ($r->level == 2) {
$tab[$r->parent][4][$r->ordered] = array($r->id,$r->name);
} elseif ($r->level == 3) {
$tab[$r->cat][4][$r->parent][2][$r->ordered] = array($r->id,$r->name);
}
}
foreach ($tab as $key => $value) {
?>
<li data-menu="<?= $value[0]; ?>" class="<?= $value[2]; ?> menu-item">
<span class="material-icons-outlined"><?= $value[3]; ?></span>
<span class="titre_menu"> <?= $value[1]; ?></span>
<ul id="sub_menu<?= $value[0]; ?>" class="box_sub_exp <?= $value[2]; ?>">
<?php foreach ($value[4] as $ke => $val) { // SUB MENU POSITION 4 ?>
<li class="<?= $value[2]; ?> submenu-item"><a href="page.php?=<?= $val[0]; ?>"><?= $val[1]; ?></a>
<?php if(!empty($val[2])) { // IS A MENU IN POSITION 2 ?>
<ul class="box_sub_sub_exp">
<?php foreach ($val[2] as $k => $v) { // SUB MENU POSITION 2 ?>
<li class="<?= $value[2]; ?> submenu-item"><a href="page.php?=<?= $v[0]; ?>"><?= $v[1]; ?></a></li>
<?php } ?>
</ul>
<?php } ?>
</li>
<?php } ?>
</ul>
</li>
<?php } ?>
</ul>
</nav>
</section>
On the first sub menu everything is OK. But on the second, the first line is missing, on the third 2 first lines are missing, etc... I think there is a problem with my loop, could you please help me to find it ?
FIXED : the problem was in the request, not "ORDER BY ordered" but by "id"
Upvotes: 0
Views: 527
Reputation: 879
Even if you set a numeric key with $r->ordered, you have to sort your table before your display loop ! Give a numeric key to a table line doesn't "auto-sort" it on loop.
Try using ksort() on $tab before your display foreach. So it's will use keys you've define and sort your table in order.
Upvotes: 2