CODEWITHSUNDEEP
javascriptreactjsthree.jstrigonometry
otto
otto

Reputation: 2043

Three.js, calculate sphere from polar coordinates

I am using three.js to calculate a sphere. I am using two for loops, one for theta and one for phi, and then I am transforming the polar coordinates to Cartesian coordinates. For every calculated point I add a Point. The result is not a sphere.

This is the nested for loop:

const distance = 1000;
for (var i = 0; i < 360; i += 10) {
  for (let j = 0; j < 360; j += 10) {
    let theta = i * (Math.PI / 180);
    let phi = j * (Math.PI / 180);
    let x = Math.sin(theta) * Math.cos(phi) * distance;
    let y = Math.sin(theta) * Math.sin(phi) * distance;
    let z = distance * Math.sin(phi);
    const lightSphere = new THREE.Mesh(sphereGeometry, sphereMaterial);
    lightSphere.position.set(x, y, z);
    scn.add(lightSphere);
  }
}

And here is the full code, including the result: Link

Upvotes: 2

Views: 687

Answers (1)

Rabbid76
Rabbid76

Reputation: 211166

j must be in range [-90, 90] 9instead of [0, 260]. Notice that you are creating slices (360 °) from the South Pole to the North Pole (180 °).

You must compute the sin(theta) and the cos(theta) and multiply both with cos(phi):

let x = Math.sin(theta) * Math.cos(phi) * distance;
let y = Math.sin(theta) * Math.sin(phi) * distance;

let x = Math.cos(theta) * Math.cos(phi) * distance;
let y = Math.sin(theta) * Math.cos(phi) * distance;

Complete algorithm:

const distance = 1000;
for (var i = 0; i < 360; i += 10) {
    for (let j = -90; j < 90; j += 10) {
        let theta = i * (Math.PI / 180);
        let phi = j * (Math.PI / 180);
        let x = Math.cos(theta) * Math.cos(phi) * distance;
        let y = Math.sin(theta) * Math.cos(phi) * distance;
        let z = distance * Math.sin(phi);
        const lightSphere = new THREE.Mesh(sphereGeometry, sphereMaterial);
        lightSphere.position.set(x, y, z);
        scn.add(lightSphere);
   }
}

You create circles (slices) using Polar coordinate (distance, theta). The Cartesian coordinate can be get by:

xc = cos(theta) * distance
yc = sin(theta) * distance

Finally you do something similar for the sphere:

x = xc * cos(phi)
y = yc * cos(phi)
z = sin(phi) * distance

Upvotes: 1

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