CODEWITHSUNDEEP
javascriptarrays
Khusni Ja'far
Khusni Ja'far

Reputation: 35

Generate list of numbers with a character in between every nth numbers

I am trying to generate a string with the numbers from 1 to 1000 with the character '*' after every 5th numbers e.g.,

1 2 3 4 5 * 6 7 8 9 10 * 11 12 13 14 15 * 16 17 18 19 20 * …

Here's my attempt but as you can it is not working as expected:

const insertCharacter = () => {
    let contain = [];
    let new_value;
    for (let i = 1; i <= 1000; i++) {
         contain += [i];
         if (contain.length)
         contain.toString()
         let parts = contain.match(/.{0,5}/g);
         new_value = parts.join("*");
    }
    return new_value;
}
console.log(insertCharacter());

Upvotes: 0

Views: 394

Answers (6)

customcommander
customcommander

Reputation: 18961

Assuming you don't want the trailing character, you could simply do:

Array.from(Array(1000 / 5),
  (_, i) => (i *= 5, `${i+1} ${i+2} ${i+3} ${i+4} ${i+5}`))
    .join(' * ');

We don't need to iterate 1000 times: we know all the numbers already and we know we'll have 200 groups of 5 numbers each. We just need to produce those groups and join them up together.

But there are many issues with this:

  • The interval is hardcoded
  • The separator is hardcoded
  • What if we can't split evenly the numbers?

Let say we need to insert a | after every 4th numbers of 10 numbers:

1 2 3 4 | 5 6 7 8 | 9 10

We have 2 groups of 4 numbers each and 1 group with the last two numbers.

(I am going to annotate these examples so you can hopefully connect them with the full example below)

The first two groups can be produced as follow:

Array.from(Array(Math.floor(10 / 4)), (_, i) => (i*=4, [i+1, i+2, i+3, i+4].join(' ')))
//               ^^^^^^^^^^^^^^^^^^                    ^^^^^^^^^^^^^^^^^^^^
//               imax                                  tmpl
//                                              ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
//                                              nseq
//
//=> ['1 2 3 4', '5 6 7 8']

The last group with:

Array(10 % 4).fill(0).map((_, i) => Math.floor(10 / 4) * 4 + i + 1).join(' ')
//    ^^^^^^                        ^^^^^^^^^^^^^^^^^^
//    tmax                          imax
//                                  ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
//                                  nseq
//
//=> '9 10'

Then you basically do:

['1 2 3 4', '5 6 7 8'].concat('9 10').join(' | ')
//=> '1 2 3 4 | 5 6 7 8 | 9 10'

Demo

console.log("sprintnums(10, 7, '|') -> " + sprintnums(10, 7, '|'));
console.log("sprintnums(10, 4, '|') -> " + sprintnums(10, 4, '|'));
console.log("sprintnums(10, 2, '|') -> " + sprintnums(10, 2, '|'));
console.log("sprintnums(10, 1, '|') -> " + sprintnums(10, 1, '|'));

console.log(`

  In your case:
  
${sprintnums(1000, 5, '*')}

`);
<script>
function sprintnums(n, x, c) {
  const tmpl = Array(x).fill(0);
  const nseq = (arr, mul) => arr.map((_, i) => mul * x + i + 1).join(' ');
  const imax = Math.floor(n / x);
  const tmax = n % x;
  const init = Array.from(Array(imax), (_, mul) => nseq(tmpl, mul));
  const tail = tmax ? nseq(Array(tmax).fill(0), imax) : [];
  return init.concat(tail).join(` ${c} `);
}
</script>

Upvotes: 0

Tigger
Tigger

Reputation: 9130

Older JavaScript format version, but still valid.

The % is called a Remainder and is the key here.

Sample code is only counting to 50.

Edit: Changed to commented version from mplungjan.

Edit 2, for comment from georg. If you do not want a trailing Asterisk, some options:

  • count to 999, then add 1000 to the result
  • use result.substring(0,result.length-2)

var i, result = "";
for(i=1;i<51;i++){
  result += i + (i % 5 ? " " : " * ");
}
console.log(result);

Upvotes: 2

Tim Biegeleisen
Tim Biegeleisen

Reputation: 522817

I would suggest using the modulus here:

var output = "";
for (var i=1; i <= 1000; ++i) {
    if (i > 1 && i % 5 == 1) output += " *";
    if (i > 1) output += " ";
    output += i;
}
console.log(output);

Upvotes: 2

S B RAKESH RATH
S B RAKESH RATH

Reputation: 477

let str = '';
for(let i = 1; i <=1000;i++){
  str+=i;
  if(i - 1 % 5 ===0) str+='*';
}
console.log(str)

Upvotes: -2

Dibash Sapkota
Dibash Sapkota

Reputation: 665

check this code

function insertChar() {
  let res = '';
  for (let i = 0; i < 100; i++) {
    res += i;
    if (i % 5 == 0) {
      res += '*'
    }
  }
  return res;
}
console.log(insertChar());

Upvotes: -1

Kirill Savik
Kirill Savik

Reputation: 1278

Please refer this code.

const result = [...Array(1000)].map((val, index) => (index + 1) % 5 === 0 ? index + 1 + " *" : index + 1);
console.log(result.join(' '));

Upvotes: 1

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