CODEWITHSUNDEEP
pythondictionary
Stackcans
Stackcans

Reputation: 351

Flatten out keys into a single key and splitting their values by lists

Suppose I have a dictionary like so:

{'a':['data', 1, 2, 3],
 'b':['data2', 4, 3, 2, 1, 0],
 'c':['data3', 3, 4, 5, 6]}

And I wanted to to be compressed likeso:

{'letters':['a','b','c'],
 'values':[['data', 1, 2, 3], ['data2', 4, 3, 2, 1, 0], ['data3', 3, 4, 5, 6]]}

Where letters and values can be any arbitrary names set for the key.

Upvotes: 0

Views: 43

Answers (2)

Alain T.
Alain T.

Reputation: 42143

You could use zip to combine your key names with the content of the dictionary items:

d = {'a':['data', 1, 2, 3],
 'b':['data2', 4, 3, 2, 1, 0],
 'c':['data3', 3, 4, 5, 6]}

d = dict(zip(('letters','values'),zip(*d.items())))

print(d)
{'letters': ('a', 'b', 'c'), 
 'values': (['data', 1, 2, 3],['data2', 4, 3, 2, 1, 0],['data3', 3, 4, 5, 6])}

Upvotes: 1

mozway
mozway

Reputation: 260410

Assuming:

d = {'a':['data', 1, 2, 3],
     'b':['data2', 4, 3, 2, 1, 0],
     'c':['data3', 3, 4, 5, 6]}

you can use:

out = {'letters': list(d.keys()),
       'values':  list(d.values())
       }

output:

>>> out
{'letters': ['a', 'b', 'c'],
 'values': [['data', 1, 2, 3], ['data2', 4, 3, 2, 1, 0], ['data3', 3, 4, 5, 6]]
}

Upvotes: 3

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