CODEWITHSUNDEEP
variablesmoduleansible
user3880406
user3880406

Reputation:

How to declare a variable for service_facts

Below is the sample ansible playbook I use to check the service status using service_facts module and it worked well. Here I need support to define the service name as variable, but when I define it is giving error, VARIABLE NOT DEFINED:

---
- name: Check service status
  hosts: all
  gather_facts: no
  tasks:
    - name: Service Facts
      service_facts:

    - debug:
        var: ansible_facts.services['firewalld.service']['status']

I need "firewalld.service" to be declared under vars section below tasks, tried various options but it is not giving the expected output. I tried below option but it is not working.

---
- name: Check service status
  hosts: all
  gather_facts: no
  vars:
    - SERVICE: firewalld.service
  tasks:
    - name: Service Facts
      service_facts:

    - debug:
        var: ansible_facts.services[SERVICE]['status']

Upvotes: -1

Views: 5694

Answers (2)

Temirlan Bolurov
Temirlan Bolurov

Reputation: 11

You can run some tasks using conditionals, for example:

  - name: Get service_facts
    service_facts:

  - name: Open some port
    firewalld:
      port: "{{ some_port }}/tcp"
      permanent: yes
      immediate: yes
      offline: no
      state: enabled
    when: 
      - ansible_facts.services['firewalld.service'].state == 'running'
      - ansible_facts.services['firewalld.service'].status == 'enabled'

Upvotes: 1

DaDummy
DaDummy

Reputation: 64

To answer your main question: vars expects a dict, not a list:

---
- name: Check service status
  hosts: all
  gather_facts: no
  vars:
    SERVICE: firewalld.service
  tasks:
    - name: Service Facts
      service_facts:

    - debug:
        msg: "{{ services[SERVICE]['status'] }}"

Additionally you need to use debug:msg as others have already mentioned.

Upvotes: 0

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