CODEWITHSUNDEEP
python
jaxan
jaxan

Reputation: 45

Using a list as parameters for a function


I'm have a list like this ['a1,b1,c1', 'a2,b2,c2', 'a3,b3,d3']
and I'm trying to either write a function or a for loop that will take each set up these numbers as inputs
so for example the first time it runs a=a1, b=b1, c=c1, the second time it'll run a=a2, b=b2 c=c2 as inputs

I've seen a few threads using functions with asterisks like this some_func(*params)
but I don't see how to make it a loop that kind of takes a combination of inputs like how I wanted it to

or would using a dict be able to address and do this?

an example would be like (sorry not making it superr specific and concrete)


def apply(a, b, c):

x = something
y = something_else

(hello, there) = somefunction(x, y, size=a) 

sky = anotherfunction(beta[1], put=b, call=c)

any help is appreciated, or if there has been a similar question before, happy for it to be linked

Upvotes: 0

Views: 649

Answers (2)

Was
Was

Reputation: 536

Suppose you have a list strings and function func

strings = ['a1,b1,c1', 'a2,b2,c2', 'a3,b3,d3']

def func(a, b, c):
    # your function
    pass

Structure will be

for string in string:
    func(*map(int, string.split(",")))

the map(int, string.split(",")) will split string and make a list like [1, 2, 3] for '1,2,3'.

Then the * symbol will spread the numbers one for each parameter, for list [1, 2, 3] will call the function like func(a=1, b=2, c=3).

Upvotes: 1

Dani Mesejo
Dani Mesejo

Reputation: 61910

If I understood correctly, use variadic arguments as follows:

def fun(*args):
    """Toy function"""
    return sum(args) + 10


arguments = ["1,2,3", "1,5,6"]

for argument in arguments:
    res = fun(*map(int, argument.split(",")))
    print(res)

Output

16
22

The expression:

map(int, argument.split(","))

creates an iterable of integers from the argument string. The * unpacks these arguments.

Upvotes: 1

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