CODEWITHSUNDEEP
javascript
carl.hiass
carl.hiass

Reputation: 1764

Getting methods on an instance

From the following code:

let n = 1234.567;
console.log(Object.getOwnPropertyNames(Number.prototype));
console.log(Object.getPrototypeOf(n));
console.log(Object.getPrototypeOf(5));

The first console.log prints the properties, but the second and third line just print {}. Why is this so? Is there a name to directly inspect the variable or number without having to refer to the base type, such as Number.prototype ?

Upvotes: 0

Views: 30

Answers (1)

CertainPerformance
CertainPerformance

Reputation: 370679

The second and third line only appear to print empty objects due to how the Stack Snippet console operates - the actual browser console of Chrome, Firefox, Safari, or whatever browser you wish will be much more informative. When debugging things and logging objects, if you want the most informative interface, use the actual browser console.

Both of those lines really do point to Number.prototype:

enter image description here

console.log(
  Object.getPrototypeOf(5) === Number.prototype
);

Upvotes: 1

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