CODEWITHSUNDEEP
bashshell
niskh
niskh

Reputation: 47

replace string between two delimiters shell in a certain position in shell

How do I replace a string between two delimiters?

In a line wherestrings are separated by ";" ,I'd like to replace the string in the 3rd position by another string($new_value) The string in the 3rd position can appear multiple times in the same line but it should only be changed in the 3rd position

I've tried

echo $laligne | awk -v repl=${new_value} -F ";" '{ printf("%s;%s;%s;%s;%s",$1,$2,repl,$4,$5)}' >> file.txt

and

old_value=`echo $line | awk '{split($0,a,";");print a[3]}'`
echo $laligne | awk -F ";"  '{gsub($old_value,$new_value,$3)}1' OFS=";" >> file.txt  

when checking the file content ,I find the line unchanged

Can you help please?

Upvotes: 0

Views: 513

Answers (2)

maleterian
maleterian

Reputation: 188

Elements are separated by ";" so regexp "[^;]+" will give them to us and we need 3rd :

$ echo "1  ;2    ;3   ;4   ;5   ;6   " | sed "s/[^;]\+/replace/3"
1  ;2    ;replace;4   ;5   ;6

Upvotes: 1

markp-fuso
markp-fuso

Reputation: 35006

Assumptions:

  • want to change field #3 in all lines (assuming this code may be applied against a ;-delimited file that contains multiple lines)
  • do not know how many fields may exist in a line

Keeping with an awk solution whereby we simply replace field #3 ($3) with the new value:

$ laligne='a;b;c;d;e;f'
$ awk -v repl='new_value' 'BEGIN {FS=OFS=";"} {$3=repl; print}' <<< "${laligne}"
a;b;new_value;d;e;f

Upvotes: 3

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