CODEWITHSUNDEEP
iosswiftuiimageviewuiimage
Sam
Sam

Reputation: 526

Get visible part of UIImageView as UIImage in Swift

In my app, I'm trying to implement a crop feature. So now I need to convert UIImageView's visible part to UIImage. Here's a screenshot from the UI debugger.

enter image description here

I've tried to achieve it with this function, but it doesn't work.

func imageFromImageView(imageView: UIImageView)  -> UIImage? {
   UIGraphicsBeginImageContext(imageView.frame.size)
    let context = UIGraphicsGetCurrentContext()!
    context.rotate(by: 2 * .pi)
    
    imageView.layer.render(in: context)
    
    let image = UIGraphicsGetImageFromCurrentImageContext()
    return image
}

Upvotes: 2

Views: 650

Answers (1)

Jayesh Patel
Jayesh Patel

Reputation: 1104

You can use bellow extension:

private var rendererKey: UInt8 = 0
extension UIView {
    var renderer: UIGraphicsImageRenderer! {
         get {
             guard let rendererInstance = objc_getAssociatedObject(self, &rendererKey) as? UIGraphicsImageRenderer else {
                self.renderer = UIGraphicsImageRenderer(bounds: bounds)
                return self.renderer
             }
             return rendererInstance
        }
        set(newValue) {
            objc_setAssociatedObject(self, &rendererKey, newValue, objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN)
        }
    }
    func snapImageView() -> UIImageView {
        let img:UIImage = renderer.image { ctx in
         DispatchQueue.main.async { 
              layer.render(in: ctx.cgContext)
          }
        }
        let imageView:UIImageView = UIImageView(image: img)
        imageView.frame = renderer.format.bounds
        imageView.clipsToBounds = true
        return imageView
    }
}
// Generate image and image view of any view instance
let anImageView = yourView.snapImageView()

Upvotes: 1

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