Reputation: 1609
I have a task of sorting an array of numbers in both ascending and descending order. The challenge is, I can't use the built-in sort function, but loop through the array with for-loops instead.
I am a total newbie when it comes to PHP and this task straight off baffles me. Here is the code I'm supposed to work with:
<?php
$arr = $_GET['arr'];
$table = explode(',', $arr);
$count = count($table);
// What I tried to work with, didn't get to work:
for ($i = 0; $i < $count; $i++) {
for ($j = $i + 1; $j < $count; $j++) {
if ($table[$i] > $table[$j]) {
$temp = $table[$i];
$table[$i] = $table[$j];
$table[$j] = $temp;
$asc = implode("," $temp);
}
}
}
echo "Ascending: $asc";
echo "Descending: $desc";
?>
Any clue why this doesn't run? At some point, I got the first (largest) number in the array with the echo, but don't really know what broke that either.
Upvotes: 0
Views: 5085
Reputation: 28206
Move the line
$asc = implode(",", $table);
from its current location below the outer for
loop and maybe add the line
$desc = implode(",", array_reverse($table));
to get the descending sort order.
Upvotes: 1
Reputation: 17586
Many ways to make it. One solution you will find in the code below. you will certainly notice that the sorting depends only on one operator. Therefore, you can build a function out of it by specifying the sorting as a parameter. function(array $array, string $sort) {}
$arr= array(112,21,130,140,2,42);
for($i=0; $i<count($arr)-1; $i++)
{
for($j=0; $j<count($arr)-1; $j++)
{
if($arr[$j] < $arr[$j+1]){
$temp= $arr[$j+1];
$arr[$j+1]= $arr[$j];
$arr[$j]= $temp;
}
}
}
print_r($arr);
Output:
Array
(
[0] => 140
[1] => 130
[2] => 112
[3] => 42
[4] => 21
[5] => 2
)
$arr= array(112,21,130,140,2,42);
for($i=0; $i<count($arr)-1; $i++)
{
for($j=0; $j<count($arr)-1; $j++)
{
if($arr[$j] > $arr[$j+1]){
$temp= $arr[$j+1];
$arr[$j+1]= $arr[$j];
$arr[$j]= $temp;
}
}
}
print_r($arr);
Output
Array
(
[0] => 2
[1] => 21
[2] => 42
[3] => 112
[4] => 130
[5] => 140
)
Upvotes: 1