CODEWITHSUNDEEP
javaspring-integrationpayloadspring-integration-dsl
anon
anon

Reputation:

Routing the message with List Generic payloads using payload-type-router in spring-integration

I'm trying to use the payload-type-router in xml based config of a legacy app and the application neither route to the specific channel nor throw any error at that instance. can we route the message of type List<?> using payload-type-router using XML configuration. I have n't found much examples in the doc as it only mentions routing using Integer, String classes but not with List.

 <int:payload-type-router input-channel="run-router-channel">
        <int:mapping type="com.foo.req.BlRunnerRequest" channel="runner-channel"/>
        <int:mapping type="java.util.List" channel="run-channel"/>  <!-- can spring integration support this approach-->
 </int:payload-type-router>

Thanks in advance. What could be the alternatives for this kind of routing in XML ?

Upvotes: 0

Views: 362

Answers (1)

Artem Bilan
Artem Bilan

Reputation: 121442

Yes. We can. I have just modified the unit test in the project to this:

<payload-type-router id="router" input-channel="routingChannel">
    <mapping type="java.lang.String" channel="channel1" />
    <mapping type="java.lang.Integer" channel="channel2" />
    <mapping type="java.lang.Number[]" channel="channel3" />
    <mapping type="java.lang.Long[]" channel="channel4" />
    <mapping type="java.util.List" channel="channel5" />
</payload-type-router>

The I do this in the test method:

testService.foo(new GenericMessage<>(new ArrayList()));
PollableChannel channel5 = (PollableChannel) context.getBean("channel5");
assertThat(channel5.receive(100).getPayload()).isInstanceOf(List.class);

Probably something else is going on in your case and that request payload is really not a java.util.List.

Also router has this logic when it cannot deliver the message to some channel:

    if (!sent) {
        getDefaultOutputChannel();
        if (this.defaultOutputChannel != null) {
            this.messagingTemplate.send(this.defaultOutputChannel, message);
        }
        else {
            throw new MessageDeliveryException(message, "No channel resolved by router '" + this
                    + "' and no 'defaultOutputChannel' defined.");
        }
    }

Since I don't see a defaultOutputChannel configuration from your code snippet, that only means a MessageDeliveryException is thrown. If you don't see it in your case, then you swallow it somehow.

Upvotes: 1

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